Accelerate nested bsxfun double loop?

조회 수: 23 (최근 30일)
andrej
andrej 2013년 10월 7일
편집: Matt J 2013년 10월 8일
I have a simple double loop that requires multiple 'repmat' tasks in each iteration. I'm currently using bsxfun to avoid repmats, but have found it to be only a little faster than repmat/elementwise multiplication.
Any suggestions on speeding this up?
n = 200;
U = rand(n);
M = zeros(n); % preallocate matrix
a = rand(1,n);
b = rand(1,n);
SZI = bsxfun(@times,a,b');
for j = 1 : n
j
for i = 1 : n
if i ~= j
plusvec = U(j,:).^2 - U(i,:).*U(j,:);
timesvec = U(i,:) - U(j,:);
M(i,j) = sum(sum(SZI.*(bsxfun(@plus,bsxfun(@times,U,timesvec),plusvec))));
end
end
end

답변 (2개)

Sean de Wolski
Sean de Wolski 2013년 10월 7일
편집: Sean de Wolski 2013년 10월 7일
Usually two dimensional:
bsxfun(@times
Can be replaced with matrix multiplication:
SZC = b'*a;
isequal(SZC,SZI)
ans =
1
More Being a fan of "ez" speedups, I turned the outer for-loop into a parfor-loop:
With two for-loops:
timeit(@()A89455(200),0)
ans =
6.3238
With the outer loop being a parfor-loop with four local workers:
timeit(@()A89455(200),0)
ans =
3.7519
A89455 is your code in a function taking n as an input.

Matt J
Matt J 2013년 10월 7일
편집: Matt J 2013년 10월 8일
Without loops:
tic;
a=a(:);
Ut=U.';
S=U*spdiags(a,0,n,n)*Ut;
S=bsxfun(@minus,diag(S).',S)*sum(b);
c=(b*U)*bsxfun(@times,Ut,a);
T=bsxfun(@minus,c(:),c);
M=S+T;
toc;
%Elapsed time is 0.002864 seconds.

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by