필터 지우기
필터 지우기

Info

이 질문은 마감되었습니다. 편집하거나 답변을 올리려면 질문을 다시 여십시오.

Can someone help me to implement this algorithm I have tried to but get errors

조회 수: 1 (최근 30일)
Martin Park
Martin Park 2013년 10월 7일
마감: MATLAB Answer Bot 2021년 8월 20일
Algorithm
Last code = 255
Series = First input character
While not end of while
character = next input character
if (series + character in code table)
series = series + character
else
output = code for series
add series and character to code table
series = character
end
end
output = code for series
Here is my code:
a=[39 39 126 126;39 39 126 126;39 39 126 126;39 39 126 126];
[f,g]=size(a);
total = f*g;
count=1;
imgchar= a(:)';
lastcode = 255;
tel = 1;
reeks = imgchar(1,1);
reekstr = num2str(reeks);
for j = 2:total
kodetabel{j}= strcat(' ');
reekskar{j}= strcat(',');
end
for i=2:total
karakter(1,i)=imgchar(1,i);
karstr = num2str(karakter(1,i));
reekskar{i} = strcat([reekstr,' ',karstr]);
waar = 0;
for k=2:total
if reekskar{i}==kodetabel{k}
reeks= reekskar{i};
waar=1;
end
end
if waar==0
output{tel}=reekstr;
kodetabel{i}=reekskar{i};
lastcode = lastcode+1;
kodetabelnr{i}=lastcode;
reeks=karakter(1,i);
tel = tel+1;
end;
end;
output{tel}=reeks;
  댓글 수: 2
Laurent
Laurent 2013년 10월 7일
What is the error you get and in which line does it happen?
Martin Park
Martin Park 2013년 10월 7일
Error using == Matrix dimensions must agree.
Error in lzw (line 29) if reekskar{i}==kodetabel{k}

답변 (2개)

Laurent
Laurent 2013년 10월 7일
It depends a bit on what result you want, but if you change that line to
if strcmp(reekskar{i},kodetabel{k})
the script runs. I don't know if this what you want, but at least there is a result. If you want something else, please tell us the result that you expect.
  댓글 수: 3
Martin Park
Martin Park 2013년 10월 7일
series in my code is named reeks and character is named karakter and code table is kode tabel
Martin Park
Martin Park 2013년 10월 7일
when following the algorithm above i get the output

Martin Park
Martin Park 2013년 10월 7일
Can anyone help me please

이 질문은 마감되었습니다.

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by