how to find integral

조회 수: 1 (최근 30일)
bhanu kiran vandrangi
bhanu kiran vandrangi 2021년 8월 3일
답변: Walter Roberson 2021년 8월 4일
74513/(10000*sign(0.99966444607707671821117401123047*e + 15567.00356006622314453125*d*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 99966.4446048736572265625*e*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 143208.73040008544921875*d*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 919819.01861572265625*e*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 6144.93734991550445556640625*d*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 79516.50818634033203125*e*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 1)*(0.99966444607707671821117401123047*e + 15567.00356006622314453125*d*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 99966.4446048736572265625*e*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 143208.73040008544921875*d*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 919819.01861572265625*e*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 6144.93734991550445556640625*d*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 79516.50818634033203125*e*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 1))
my equation looks big but it is in fractional form , how to integrate (from 0 to 2000)this w.r.t 't' alone and by keeping 'd' and 'e' as constant
  댓글 수: 2
Anna Case
Anna Case 2021년 8월 3일
If 'd' and 'e' are defined, you can use numerical integration.
bhanu kiran vandrangi
bhanu kiran vandrangi 2021년 8월 4일
d and e are variables which vary from [0,1] , i need the equation that comes after integration as a function of d,e so that i can optimize the equation to find the suitable values of d,e in that range[0.1]

댓글을 달려면 로그인하십시오.

답변 (1개)

Walter Roberson
Walter Roberson 2021년 8월 4일
First let us enter the equation in without losing precision
S = '74513/(10000*sign(0.99966444607707671821117401123047*e + 15567.00356006622314453125*d*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 99966.4446048736572265625*e*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 143208.73040008544921875*d*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 919819.01861572265625*e*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 6144.93734991550445556640625*d*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 79516.50818634033203125*e*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 1)*(0.99966444607707671821117401123047*e + 15567.00356006622314453125*d*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 99966.4446048736572265625*e*(0.000000006195369979837203611161555727449*exp(-0.031830333683444479966526650949188*t) + 0.000010273947474104261345928534865379*exp(-9.113261252370440103050611146962*t) - 0.00000028014284413763190784152357082348*exp(-0.21190841394611541708927664531825*t)) - 143208.73040008544921875*d*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 919819.01861572265625*e*(0.00000019463729288710096554382289468776*exp(-0.031830333683444479966526650949188*t) + 0.0000011273623338192706455629377160221*exp(-9.113261252370440103050611146962*t) - 0.0000013219996267133105050106678390875*exp(-0.21190841394611541708927664531825*t)) + 6144.93734991550445556640625*d*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 79516.50818634033203125*e*(0.0000061148367096475197968175052665174*exp(-0.031830333683444479966526650949188*t) + 0.0000001237056968493577269185834666132*exp(-9.113261252370440103050611146962*t) - 0.0000062385424065558581219193001743406*exp(-0.21190841394611541708927664531825*t)) - 1))';
SS = str2sym(S)
SS = 
Now let us get an idea of how the equation looks over a range of d, e, t values, to see if integration is likely to work
syms d e t
N = 40;
tvec = linspace(0,2000,N);
[D, E, T] = meshgrid(linspace(0,1,N),linspace(0,1,N),tvec);
Is = double(subs(SS,{d,e,t},{D,E,T}));
minis = min(Is(:)); maxis = max(Is(:));
[minis, maxis]
ans = 1×2
1.0e+04 * 0.0007 2.2206
levels = linspace(minis, maxis, 5);
for K = 1 : length(levels)
isosurface(D, E, T, Is, levels(K));
end
xlabel('d'); ylabel('e'); zlabel('t');
legend(string(levels));
colorbar()
Unfortunately at this angle, the yellow is hidden, but we know it exists somewhere.
That back wall... let's get an idea of what the function looks like there
T1 = linspace(0,2000,5000);
I11 = double(subs(SS, {d,e,t}, {1, 1, T1}));
plot(T1, I11)
Looks like it settles in near 22000 for each value, so the integral would be roughly 22000 * 1700 or so, on the order of 4e7
We can do a numeric integration over t, over a range of d and e values
IntI = trapz(tvec, Is, 3);
surf(D(:,:,1), E(:,:,1), IntI); xlabel('d'); ylabel('e'); zlabel('integral')
4E7 is pretty much what we estimated just a moment ago.
This tells us that to maximize the integral, we should concentrate on e near 1; it is not obvious at the moment whether d has much effect.
I would suggest redoing a plot using e = 1 (constant) and using a range of d and using a denser range of t values, and using trapz() to do numeric integration; this will give you better information about which range is worth looking more closely at.

카테고리

Help CenterFile Exchange에서 Numerical Integration and Differentiation에 대해 자세히 알아보기

태그

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by