Application compiler: Command line Input type options missing

I am using Application compiler for generating a standalone application. I'm following the documenttaion available here

https://in.mathworks.com/help/compiler/create-and-install-a-standalone-application-from-matlab-code.html

I don't find the `Command line Input type options` shown here ( https://in.mathworks.com/help/compiler/create-and-install-a-standalone-application-from-matlab-code.html ) above Additional installer options.

I'm using 2021a.

Could someone help me with this? I'd like to include `Command line Input type options` to pass input arguments to the executable file.

Answer 1

[Kojiro Saito]

"Command line input type options" will be shown if m file is a function.

In the documentation example which you mentioned, the magicsquare.m file is a function.

function m = magicsquare(n)

if ischar(n)
    n=str2double(n);
end
m = magic(n);
disp(m)

It seems that your main.m is a script file.

For detail about script vs function, this document will be helpful.

[Deepa Maheshvare]

Hi @Kojiro Saito,

Many thanks for the clarification.

If I may ask a follow up question

I have a class with all the settings defined and this class is accessed from the main script and by other functions that are called in the main script .

classdef classname
    properties (Constant)
     end
    
    methods(Static) 
        function test_run = select_run
            test_run = struct(...
            'test1',false,...
            'test2',false,...
            'test3',true,...
             );
        end 
    end

In the usual way, I directly change the settings in my class depending on the test case that I want to run.

i.e if I want to run `test1` , I set

test_run = struct(...
            'test1',true,...
            'test2',false,...
            'test3',false,...
             );

Here is what I intend to do while generating the standalone executable. Change main.m from `script` to `function`. And I want to change the settings of `test_run` in the ``classname` class via the main function (main(arg)).

Could you please suggest what's the best way to do this?

[Kojiro Saito]

@Deepa Maheshvare

I am not sure I can clearly understand, but how about setting test1, test2 and test3 in properties of the class and accessing the class from main function?

classdef classname
    properties
       test1
       test2
       test3
    end
    methods(Static) 
        function test_run = select_run
            test_run = struct(...
            'test1',false,...
            'test2',false,...
            'test3',true,...
             );
        end 
    end
end

function out = main(in1)    
    % Use input variable
    % hogehoge = in1;
    
    myClass = classname;
    % Initialize struct
    myClass = myClass.select_run;
    
    % Change struct
    myClass.test1 = true;
    myClass.test3 = false;
    
    %out = blah-blah-blah;
    %disp(out)
end

[Deepa Maheshvare]

@Kojiro Saito Thank you , I'm sorry but I am really confused at this point. I am sharing a simple exmaple below. Hope I can explain my doubt clearly through this example

I want to do the following: define the value of Number in `classname` properties from another function `main`.

function main(arg)
  classname.get_Number(arg)
end

classdef classname
    properties (Constant)
        %use a struct to store the defaults to keep all your static
        %properties in one place
      Number=classname.get_Number;
    end
    methods(Static)
        function val=get_Number(arg)
            val=arg;
        end
    end
end

>>main(10)

Expected result:

When I call classname.Number from other functions or class, I want it to return 10.

[Kojiro Saito]

This document(Developing Classes — Typical Workflow) will be helpful.

There various ways to implement your class.

Simple way is the following.

classdef classname
    properties (SetAccess = private)
        Number
    end
    methods
        function val=classname(arg)
            val.Number=arg;
        end        
    end
end

function out = main(arg)    
    myClass = classname(arg);
    out = myClass.Number;
end

By the way, it's getting going away from the original question, so if you have further question, it's better to post it as another question.