How to convert the digits of a number in a higher number base to an array

I converted 32 to base 18 using the code

A=dec2base(32,18)

and the output was

'1B'

I want to convert the digits of 1B to an array [1 B]. so i used the code

num2str(A)-'0'

Which gave me an output

ans =

     1    21

Instead of ans= 1 B. Please help.

[Rik]

B is not a number, so what do you want? You already have '1B'. What do you want to do next?

Newer releases of Matlab do support hexadecimal notation, but otherwise, only base 10 numbers are allowed outside of text datatypes.

[Ernest Adamtey]

I want 1 and B to be seperated in an array form. I'm using MATLAB Version: 9.8.0.1323502 (R2020a).

[Rik]

They are already:

A='1B';
A(1)

ans = '1'

A(2)

ans = 'B'

So again: what do you want to do that would require a conversion?

[Ernest Adamtey]

I want to use an if statement and a fo loop on the digits of A. Its easier to do this if A is an array of its digits.

for example

for A=[1 B E];
if A==B
disp('yes')
end
end

But this I cant do this if A is not an array

[John D'Errico]

They ALREADY ARE separate array elements. It is just that MATLAB is given a character string of two elements, and displays it as a character string of two elements. The version of MATLAB you are using is irrelevant.

[Rik]

Because it is already an array, your code already works with minor modification:

for A='1BE'
    A
    if A=='B'
        disp('yes')
    end
end

A = '1'

A = 'B'

yes

A = 'E'

[Ernest Adamtey]

thank you very much. It worked

[dpb]

Newer releases of Matlab do support hexadecimal notation, but otherwise, only base 10 numbers are allowed outside of text datatypes." @Rik

While not really pertinent to the discussion, Forth has the system constant BASE that lets one define the base dynamically...

BINARY
...everything here in base 2
DECIMAL
...now we're back in base 10

that is extremely handy and that I miss.

: DECIMAL  10 BASE ! ;
: HEX      16 BASE ! ;
: OCTAL     8 BASE ! ;
: BINARY    2 BASE ! ;

are the common defining words. Of course, one needs be certain DECIMAL is in effect when defining the above!!! :)

Just a sidebar into days of yore..."we now return you to your regular programming".