Discrepancy between eigenvalues and eigenvectors derived from analytical solution and matlab code.
이전 댓글 표시
Hello,
I have this matrix [ep+V/2 t*phi; t*conj(phi) eb-V/2].
The analytical solution for eigenvalues of this matrix is E=(eb+ep)/2+v*sqrt((eb-ep+V)/2+t^2*|phi|^2).
But matlab solution is different from this.
Can someone help me for solve this chalenge?
채택된 답변
추가 답변 (1개)
syms eb ep t V phi
H=[ep+V/2 t*phi; t*conj(phi) eb+V/2]
[E,v]=eig(H)
Let's check if the elements in E and v satisfy the definition of the eigenvectors and eigenvalues for H.
simplify(H*E-E*v)
The elements in E and v satisfy the definition of the eigenvectors and eigenvalues for H, so they are eigenvectors and eigenvalues of H. What did you say you expected the eigenvalues to be?
카테고리
도움말 센터 및 File Exchange에서 Linear Algebra에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!





