two arrays mapping value

조회 수: 3 (최근 30일)
Pierre
Pierre 2013년 9월 25일
Hi, I have two arrays A=[1 0.1452; 2.1 0.2487; 3.2 0.3478; 4.8 0.41123] and B=[0.4 0.5 2.5 3.5 1.7]. I wanna get the mapping value of B from A. The rule is to find the ceil value of B in first column of A and return value in second column of A.For example, the ceil value of 1.7 in first column of A is 2.1, so the mapping value is 0.2487. Finally, the mapping value of B is [0.1452 0.1452 0.3478 0.41123 0.2487]. The size of B is over 10000. Please tell me the faster and more efficient method to solve it. Thanks

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Vishal Rane
Vishal Rane 2013년 9월 25일
A((A(:,1) == min(A(A(:,1) > B(1)))),2)
  댓글 수: 1
Vishal Rane
Vishal Rane 2013년 9월 25일
편집: Vishal Rane 2013년 9월 25일
run this in a for loop by indexing B(i) or use this
arrayfun( @(x)( A((A(:,1) == min(A(A(:,1) > x))),2)), B)

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Jan
Jan 2013년 9월 25일
편집: Jan 2013년 9월 25일
B(B > max(A(:, 1)) = NaN; % B too large
[dummy, index] = histc(B, [-Inf, A(:, 1).']);
outOfRange = (index == 0)
Result = A(index(~outOfRange), 2);
I cannot test this currently. Please care about the exceptions like values of B, which are greater or equal the maximum value of A. The CEIL criterion is not fulfilled, when an element of B is exactly contained in A. But HISTC is the general way to go through.

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