# How can I code a two variable function?

조회 수: 4(최근 30일)
Eduardo Fornazieri 2021년 7월 10일
편집: ANKUR KUMAR 2021년 7월 11일
Hi, could you code this function from ?
I know I can't do it to infinity, so I choose the sum from 0 to 100. Please, help. .

댓글을 달려면 로그인하십시오.

### 채택된 답변

ANKUR KUMAR 2021년 7월 11일
편집: ANKUR KUMAR 2021년 7월 11일
You can simply use for loop to iterate x and y. Refer to the below code just for your reference. You might need to make modification as per your need.
This might be the good starting point for you to write code independently.
Anyway, I am getting some of the NaN values.
func = @(n,x,y) (((-1)^n)/((2*n + 1)^3))* sech(((2*n + 1)*pi)/2)*cosh(((2*n + 1)*pi*x)/2)*cos(((2*n + 1)*pi*y)/2);
n_upper_limit=100;
for x=1:5
for y=1:5
u(x,y) = 1- y^2 - ((32)/(pi^3))*(sum(arrayfun(@(n) func(n,x,y), 1:n_upper_limit),'omitnan'));
end
end
disp(u)
1.0e+130 * -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 1.6033 0.0000 -1.6033 -0.0000 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
% For plotting u
imagesc(u)
title('Values of u')
xlabel('x values')
ylabel('y values')
xticks([1:5])
yticks([1:5])
colorbar
set(gca,'Ydir','normal') 댓글을 달려면 로그인하십시오.

### 범주

Find more on Creating and Concatenating Matrices in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!