Why am I getting error:- Empty sym: 0-by-1

조회 수: 2 (최근 30일)
KAJAL KUMARI
KAJAL KUMARI 2021년 7월 8일
답변: Walter Roberson 2021년 7월 9일
I am trying to get the values of variables using vpasolve.
syms n1 n2 n3 n4 n5 n6 n7 n8 n9 n10 n11 n12 n13 n14 n15 n16 n17 K
eqn1 = ((0.2)^3).*n1 + ((0.22)^3).*n2+((0.23)^3).*n3+ ((0.24)^3).*n4 + ((0.25)^3).*n5+((0.26)^3).*n6+((0.27)^3).*n7+((0.28)^3).*n8+((0.29)^3).*n9+((0.3)^3).*n10+((0.31)^3).*n11+((0.32)^3).*n12+((0.34)^3).*n13+((0.35)^3).*n14+((0.4)^3).*n15+((0.42)^3).*n16+((0.45)^3).*n17==K;
eqn2 = ((0.2)^3).*n1/K==1;
eqn3 = ((0.22)^3).*n2/K==1.5;
eqn4 = ((0.23)^3).*n3/K ==4;
eqn5 = ((0.24)^3).*n4/K ==7;
eqn6 = ((0.25)^3).*n5/K ==11.4;
eqn7 = ((0.26)^3).*n6/K ==13.8;
eqn8 = ((0.27)^3).*n7/K ==15;
eqn9 = ((0.28)^3).*n8/K ==12;
eqn10 = ((0.29)^3).*n9/K ==8;
eqn11 = ((0.3)^3).*n10/K == 4.5;
eqn12 = ((0.31)^3).*n11/K ==2.5;
eqn13 = ((0.32)^3).*n12/K ==1.4;
eqn14 = ((0.34)^3).*n13/K ==1;
eqn15 = ((0.35)^3).*n14/K ==0.5;
eqn16 = ((0.4)^3).*n15/K ==0.2;
eqn17 = ((0.42)^3).*n16/K ==0.1;
eqn18 = ((0.45)^3).*n17/K==0.02;
eqn19 = n1+n2+n3+n4+n5+n6+n7+n8+n9+n10+n11+n12+n13+n14+n15+n16+n17 == 7.68e8;
eqns = [eqn1,eqn2,eqn3,eqn4,eqn5,eqn6,eqn7,eqn8,eqn9,eqn10,eqn11,eqn12,eqn13,eqn14,eqn15,eqn16,eqn17,eqn18,eqn19];
vars = [n1 n2 n3 n4 n5 n6 n7 n8 n9 n10 n11 n12 n13 n14 n15 n16 n17 K];
answer = solve(eqns,vars);
vpa(answer.n1)
vpa(answer.n2)
vpa(answer.n3)
vpa(answer.n4)
vpa(answer.n5)
vpa(answer.n6)
vpa(answer.n7)
vpa(answer.n8)
vpa(answer.n9)
vpa(answer.n10)
vpa(answer.n11)
vpa(answer.n12)
vpa(answer.n13)
vpa(answer.n14)
vpa(answer.n15)
vpa(answer.n16)
vpa(answer.n17)
  댓글 수: 1
Sharmin Kibria
Sharmin Kibria 2021년 7월 9일
I believe the system of equations do not have a solution. Check the second tip in the following.

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채택된 답변

Walter Roberson
Walter Roberson 2021년 7월 9일
There is no solution.
You have 19 equations in 18 variables.
If you solve the middle 17 equations using solve() you get solutions for the n* variables in terms of K.
When you substitute those into the first equation, you get an expression in K on the left and an expression in K on the right. The only solution for that is K = 0. Substituting K = 0 into the solutions to the middle 17 shows they must all be 0 as well.
But making the variables all 0 does not satisfy the final equation. So, no solution.

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