How to plot monthly data for 31 years on the same plot?

조회 수: 6(최근 30일)
Leo Tu
Leo Tu 2021년 6월 30일
편집: Seth Furman 2021년 7월 1일
I have a table with the first column labelled month_Date. It contains the months from Jan 1987 to Jan 2020. The Second column is just a groupcount. The third column is labelled mean_MeanSoilTemperatureAt1MdegCIDWMean and it contains the mean soil temperature for each of the months. I need to make a plot such that the x-axis is labelled with the months and the y-axis labelled soil temperature. Then, I need the lines of the plot to be each years values and for each line to be a specific colour. If anyone could help, it would be much appreciated.
  댓글 수: 1
Leo Tu
Leo Tu 2021년 6월 30일
Update: I orginally had a table called T with dates from 01/01/1987 00:00 to 01/01/2020 00:00 and I used the following script to group the dates into months and to find the mean of soil temperature for each month:
TT = groupsummary(T,1,"Month","Mean",38);
where 1 is the column number for the dates in T and 38 is the column number for soil temperature in T.
Then TT is my new table as mentioned in my original question post.

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채택된 답변

Seth Furman
Seth Furman 2021년 7월 1일
편집: Seth Furman 2021년 7월 1일
It is probably easier to store the data in a timetable and use retime to get the monthly averages.
tt = timetable(datetime(2000,1,1)+calmonths(1:100)',(1:100)')
tt = 100×1 timetable
Time Var1 ___________ ____ 01-Feb-2000 1 01-Mar-2000 2 01-Apr-2000 3 01-May-2000 4 01-Jun-2000 5 01-Jul-2000 6 01-Aug-2000 7 01-Sep-2000 8 01-Oct-2000 9 01-Nov-2000 10 01-Dec-2000 11 01-Jan-2001 12 01-Feb-2001 13 01-Mar-2001 14 01-Apr-2001 15 01-May-2001 16
tt = retime(tt,'monthly','mean')
tt = 100×1 timetable
Time Var1 ___________ ____ 01-Feb-2000 1 01-Mar-2000 2 01-Apr-2000 3 01-May-2000 4 01-Jun-2000 5 01-Jul-2000 6 01-Aug-2000 7 01-Sep-2000 8 01-Oct-2000 9 01-Nov-2000 10 01-Dec-2000 11 01-Jan-2001 12 01-Feb-2001 13 01-Mar-2001 14 01-Apr-2001 15 01-May-2001 16
Then, we can find the list of years covered by our data ...
years = unique(tt.Time.Year,'sorted')
years = 9×1
2000 2001 2002 2003 2004 2005 2006 2007 2008
... and plot them serially ...
figure
hold on
for i = 1:length(years)
ttYear = tt(tt.Time.Year == years(i),:);
plot(ttYear.Time,ttYear.Var1);
end
legend(string(years));
hold off
... or plot them against the months of the year by shifting all the datetime x-values to the same arbitrary year.
figure
hold on
for i = 1:length(years)
ttYear = tt(tt.Time.Year == years(i),:);
ttYear.Time.Year = 2000; % set all datetime x-values to the same arbitrary year
plot(ttYear.Time,ttYear.Var1);
end
xtickformat('MMM');
legend(string(years));
hold off

추가 답변(1개)

KSSV
KSSV 2021년 6월 30일
Let T be your table.
thedates = T.(1) ;
val = T.(3) ;
[Y,MO,D,H,MI,S] = datevec(thedates) ;
[c,ia,ib] = unique(Y) ;
figure(1)
hold on
for i = 1:length(c)
plot(thedates(ib==i),val(ib==i))
end
legend
  댓글 수: 2
Leo Tu
Leo Tu 2021년 6월 30일
Sorry @KSSV I made a slight error. when I try using my table (TT) I get an error regarding datevec, stating that the input was was not an array of character vectors or strings. Sorry for the confusion. When I use my orginal table (T) then I get the plot I have shown above.

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