# How to get quotient value after division without round off?

조회 수: 30(최근 30일)
Khushboo Singla 2021년 6월 19일
답변: Steven Lord 2021년 6월 19일
I want to get quotient (only integer value) after division of two numbers without rounding off.
n1 = I1(i,j) +1;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2);
end
when n1 = 157 in first line :
then in fourth line after dividing by 2 , n1 is taking 79 (157/2 = 78.5) value
but i want n1 to take 78 value.
##### 댓글 수: 2표시숨기기 이전 댓글 수: 1
dpb 2021년 6월 19일
>> n1=157;
>> fix(n1/2)
ans =
78
>>
You've done something else you've not told us about first...like an intermediate store with a rounding operation, maybe.
>> n1=157;for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2)
end
n1 =
78
n1 =
39
n1 =
19
n1 =
9
n1 =
4
n1 =
2
n1 =
1
n1 =
0
>>

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### 채택된 답변

Mouhamed Niasse 2021년 6월 19일
Hello,
I tried to execute your portion of code but, just as expected, n1 has the value 78 not 79 for me.
Try using the function 'floor' instead of 'fix', they normally give the same output for positive input values.
##### 댓글 수: 1표시숨기기 없음
Khushboo Singla 2021년 6월 19일
Thankyou so much. Though same problem persisted in my code BUT i got another solution
as I subtracted remainder(from third line) from the number(n1) everytime so that it will give only interger value after division as shown:
n = 157;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix((n1-l1(8-k1))/2)
end

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### 추가 답변(1개)

Steven Lord 2021년 6월 19일
If one or both of the numbers are stored as an integer type you could use the idivide function.
idivide(int16(157),2)
ans = int16 78

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R2021a

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