Create a matrix out of single values if a for loop?

Hello,

is it possible to create a 1xF matrix in a for loop out of single values?

n = 2;
r = 0.5;
a = 10;
b = 5;
p = [r + (a-2*r)*rand(n,1),r + (b-2*r)*rand(n,1 )];
for i = 1:n
    for j = i:n
        if i == j
            continue
        end
        H = (norm(p(i,:)-p(j,:))<=2*r)
    end
end

[KSSV]

You want to save H into a matrix you mean?

[gamer]

yes:)

[gamer]

Right now H just gives me a lot of single values back

[SungJun Cho]

You should preallocate H as a matrix and save each values into your matrix. For example,

% ...
H = zeros(n,n);
for i = 1:n
    for j = i:n
        % ...
        H(i,j) = (norm(p(i,:)-p(j,:))<=2*r)
    end
end

[gamer]

I tried it like that but it just gives me again 3 matrices back instead of one

r = 0.5; a = 0; b = 5; n = 3
p=[r + (a-2*r)*rand(n,1),r + (b-2*r)*rand(n,1)];
H = zeros(1,((n-1)*n)/2 )
for i = 1:n 
for j = i:n 
 if i == j
     continue
 end
H(1,((n-1)*n)/2) = (norm(p(i,:)-p(j,:)))
end 
end

I want the norm of (p(1,:) - p(2,:), p(1,:) - p(3,:) and p(2,:) - p(3,:) in one matrix. This is just an example for n = 3.

Answer 1

[KSSV]

r = 0.5; a = 0; b = 5; 
n = 3 ; 
p=[r + (a-2*r)*rand(n,1),r + (b-2*r)*rand(n,1)];
H = zeros(1,[]) ;
count = 0 ; 
for i = 1:n 
for j = i:n 
 if i == j
     continue
 end
 count = count+1 ; 
H(1,count) = (norm(p(i,:)-p(j,:)))
end 
end

[gamer]

Thanks:)