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Eliminate rows from an array

조회 수: 2(최근 30일)
Hi everyone
How can I cut a 31450X1 array in order to obtain the same array with a dimension of 15725X1, eliminating the second half of rows from the original array? The array is a variable I'm working with, but I can't solve that problem. I tried it creating the next code:
LEN=length(data3);
for x=1:LEN
if x>(LEN/2)
ROW=LEN;
data3(ROW,:)=[];
end
end
Where data3 is the 31450X1 array, but the matrix index is out of range for deletion

채택된 답변

Image Analyst
Image Analyst 2021년 6월 12일
To eliminate the "second half of rows" (like you asked) from your column vector, do this:
midRow = ceil(length(data3) / 2);
data3 = data3(midRow : end);
To eliminate every other row, do this:
evenRows = data3(2:2:end); % Extract even numbered rows only.
oddRows = data3(1:2:end); % Extract odd numbered rows only.
  댓글 수: 1
José Santos Pérez Leal
José Santos Pérez Leal 2021년 6월 12일
Thank you very much!!! I will analize it in order to understand your method, thank you!!

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추가 답변(1개)

Mouhamed Niasse
Mouhamed Niasse 2021년 6월 12일
Hello, this is what you tried to achieve:
data3(1+length(data3)/2:length(data3),:)=[];
Try to run below example. Hope it helps you understand.
data3=ones(31450,1); % data3 initialized as row vector of size 31450x1
size(data3)
data3(1+length(data3)/2:length(data3),:)=[]; % Eliminate second half of rows
size(data3)
  댓글 수: 1
José Santos Pérez Leal
José Santos Pérez Leal 2021년 6월 12일
Thank you very much, Mouhamed!!! I'm going to analize your method in order to understand it, thanks!!

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