How to find the 12th highest value for every year

I have a data set that I have made into a table and used the sort funtion to make it into descending order based on the year followed by the 2nd column values i.e.

2014 3.98 10.34

2014 3.93 10.24

2014 3.90 10.18

.

.

.

2006 0.61 5.05

2006 0.54 5.01

2006 0.52 4.98

2006 0.50 4.89

2006 0.50 4.79

I want to find the 12th highest value for each year (the 12th row for every year).

The number of data measurements for each year are not equal. For example, in year 2014 there might be 12000 rows but in year 2010 there may only be 11500 rows of data

Thank you in advance.

Answer 1

[Nicky Benedict]

I figured it out.

T_sort = sortrows(T,[1,2,3],'descend');

[yr,index] = unique(T_sort.Years); 
index_new = index + 11; 
hour_12 = T_sort(index_new,:);

Answer 2

[SALAH ALRABEEI]

Since you already sorted them, what you need to do now is call the first highest 12 as follows

     % Assuming the matrix is A where the 1st col is the years.
B = [];
years = unique(A(:,1));
for i = 1: length(years)
B= [B,(A(A(:,1)==years(i),12))];
end

[Nicky Benedict]

So I initialized A to be a vector for the years so I can use your code:

T_sort = sortrows(T,[1,2,3],'descend');

A = T_sort.Years;
B = [];
years = unique(A(:,1));
for i = 1: length(years)
B= [B,(A(A(:,1)==years(i),12))];
end

but I still get an error message:

Index in position 2 exceeds array bounds (must not exceed 1).

Error in Closure_depth_yearly (line 21)

B= [B,(A(A(:,1)==years(i),12))];

[SALAH ALRABEEI]

 Sorry that was my mistake. Please add replace this wth what is inside the loop   
  % 
btemp = A(A(:,1)==years(i),:);
B = [B ; btemp(12,:) ];

[Nicky Benedict]

The approach you took ended up just giving me the years but I managed to figure it out with the help of the "unique" function you had in your code. Thank you for all your help. I appreciate it. I posted my code down below if you want to know what I did.