when we call for boxplot function, is there any setting to avoid that such function that evaluates outliers, so that the red crosses will be considered part of the distributi
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Rik
2021년 6월 4일
Have you read the documentation? I expect setting Whisker to inf should do it.
And indeed it does:
boxplot([5;randn(100,1)],'Whisker',inf)
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Rik
2021년 6월 4일
What code did you try exactly?
Doesn't this work?
boxplot([path1; path2; path3; path4; path5; path6; path7; path8],group,'Whisker',inf)
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