Random sample, I want the 5% of the data per each hour
조회 수: 2 (최근 30일)
이전 댓글 표시
I have a database with 19 columns. One column has date, month, year and hour. I would like to get, per each hour, the 5% of the data. Naturaly, I would like to see all the other data, along with the column of time.
Can you help me?
I saw the comand resample, but at the moment, I am in difficulty.
댓글 수: 2
Scott MacKenzie
2021년 6월 4일
It would help if you post the data -- or, better yet, a subset of the data -- and any code you have written so far.
채택된 답변
Scott MacKenzie
2021년 6월 4일
편집: Scott MacKenzie
2021년 6월 4일
There might be a way to simplify this, but I believe the script below achieves what you are after...
% read all the data into a table
T = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/642145/Cartel1.xlsx');
% build a vector of 0s and 1s --> each 1 occurs where the hour changes
dt = datetime(T{:,3});
hr = hour(dt);
z = diff(hr);
% build a vector of the indices where the time changes
idx = find(z); % indices of 1s in z
idx = [0; idx];
% build a vector of new indices, selecting at random 5% of the rows for each hour
idxNew = [];
for i=2:length(idx)
n = round(0.05 * (idx(i) - idx(i-1)+1));
idxNew = [idxNew, randi([idx(i-1)+1, idx(i)], 1, n)];
end
% create new table with 5% of the rows for each hour
Tnew = T(idxNew,:);
With this script, your data set is now much smaller. See below. That's the general idea, right?
댓글 수: 2
Scott MacKenzie
2021년 6월 4일
@Rachele Franceschini You're welcome.
BTW, I just fixed a small bug in the answer script. The second index in each range included the first row of the following hour. It's fixed now. Good luck.
추가 답변 (1개)
KSSV
2021년 6월 4일
Let A be your data matrix.
[m,n] =size(A) ;
p = round(5/100*m) ;
idx = randsample(m,n) ;
iwant = A(idx,:)
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Startup and Shutdown에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!