How to include function in legend

조회 수: 55 (최근 30일)
Niklas Kurz
Niklas Kurz 2021년 6월 3일
댓글: Star Strider 2021년 6월 3일
I tried all possibl string2functions of Matlab, but not getting quiete the result.
Here's my best try:
syms x
F = x^2; % Definied Function
g = matlabFunction(F);
% some random steps
x = -10:0.1:10;
f = g(x);
p1 = plot(x,f);
hold on
n = 20;
C = jet(n);
for k= 1:n
p2 = plot(x,f+2*k,'Color',C(k,:));
end
% Here comes the questionable part.
legend([p1,p2],{strcat('f = ',char(F)),sprintf('f at n = %0.f',n)},...
'Interpreter','latex','FontSize',20)
Basically I want the function that I definied to be automatically updated in legend. (Pretty handy if you change f multiple times). However in my attemp I get a warning:
String scalar or character vector must have valid interpreter syntax:
f:x^2
How can the function be acknowledged by the interpreter?

채택된 답변

Star Strider
Star Strider 2021년 6월 3일
A sllightly different approach —
syms x
F = x^2; % Definied Function
g = matlabFunction(F);
% some random steps
x = -10:0.1:10;
f = g(x);
p1 = plot(x,f);
hold on
n = 20;
C = jet(n);
for k= 1:n
p2 = plot(x,f+2*k,'Color',C(k,:));
end
% Here comes the questionable part.
legend([p1,p2],{sprintf('$f = %s$',char(F)),sprintf('$f\\ at\\ n = %0.f$',n)},...
'Interpreter','latex','FontSize',20)
.
  댓글 수: 2
Niklas Kurz
Niklas Kurz 2021년 6월 3일
I reckognized 'latex(F)' instead of 'char(F)' is just more accurate at displaying functions like But either way it is working now! Just the right tweeking.
Star Strider
Star Strider 2021년 6월 3일
Great!
Thank you!

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추가 답변 (1개)

Joseph Cheng
Joseph Cheng 2021년 6월 3일
편집: Joseph Cheng 2021년 6월 3일
do you need to use latex as just using the default tex? as latex uses $ for markup of symbols i don't know if it'll take the syms function very well without some edits. if you get rid of the interpreter setting and use the default one
syms x
F = x^2; % Definied Function
g = matlabFunction(F);
% some random steps
x = -10:0.1:10;
f = g(x);
p1 = plot(x,f);
hold on
n = 20;
C = jet(n);
for k= 1:n
p2 = plot(x,f+2*k,'Color',C(k,:));
end
% Here comes the questionable part.
legend([p1,p2],{strcat('f = ',char(F)),sprintf('f at n = %0.f',n)},...
'FontSize',20)
more info can be found here in another matlab tex vs latex answers sub
  댓글 수: 1
Niklas Kurz
Niklas Kurz 2021년 6월 3일
편집: Niklas Kurz 2021년 6월 3일
Well, latex just looks more beautiful in my eyes :$

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