Help sketching equation into 3d graph
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What I got so far for the equation
Z=5-sqrt(1-x.^(2)-(y-abs(x)).^2).*cos(30.*(1-x.^(2)-(y-abs(x)).^(2)))
Then I tried these lines
x=linspace(-1,1, 200);
y=linspace(-1, 1.5, 200);
[X,Y]=meshgrid(x,y);
Z=5-sqrt(1-x.^(2)-(y-abs(x)).^2).*cos(30.*(1-x.^(2)-(y-abs(x)).^(2)))
zlim([1,6]);
surf(X,Y,Z);
It gave me "Z must be a matrix, not a scalar or vector." error.
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채택된 답변
Star Strider
2021년 6월 1일
The error it throws when I run it here is:
X, Y, Z, and C cannot be complex
This is likely because of the negative values in ‘x’ and ‘y’, however I did not do an in-depth analysis.
Dealing with that produces —
x=linspace(-1,1, 200);
y=linspace(-1, 1.5, 200);
[X,Y]=meshgrid(x,y);
Z=@(x,y) 5-sqrt(1-x.^(2)-(y-abs(x)).^(2).*cos(30*(1-x.^(2)-(y-abs(x)).^(2))));
figure
surf(X,Y,real(Z(X,Y)))
grid on
zlim([1,6])
title('Real Z')
figure
surf(X,Y,imag(Z(X,Y)))
grid on
% zlim([1,6])
title('Imag Z')
figure
surf(X,Y,abs(Z(X,Y)))
grid on
zlim([1,6])
title('|Z|')
figure
surf(X,Y,Z(X,Y))
grid on
zlim([1,6])
title('Complex Z')
.
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추가 답변 (2개)
Joseph Cheng
2021년 6월 1일
what you'll need to do is use the function meshgrid() which will then create a 2D matrix for both x and y such that you can get the pair combination of x and y of your linspace
[x y]=meshgrid(x,y);
%then do your Z
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Joseph Cheng
2021년 6월 1일
As right now
x = 1x200 matrix
y = 1x200 matrix
so since you're using .* and .^ in your Z equation you'll also get a 1x200 for Z.
using meshgrid to generate the 2D grid of x and y combinations such that you can get the range of Z values for x between -1 and 1 and y over the range of -1 and 1.5.
Girijashankar Sahoo
2021년 6월 1일
% Size of of your output Z must be 200x200 matix
% Try this code for 3D output
x=linspace(-1,1, 200);
y=linspace(-1, 1.5, 200);
for i=1:length(y)
for k=1:length(x)
Z=5-sqrt(1-x.^(2)-(y-abs(x)).^(2).*cos(30*(1-x.^(2)-(y-abs(x)).^(2))));
end
end
zlim([1,6]);
T=rand(200)
surf(x,y,T);
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