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How to I convert this time format to datetime?

조회 수: 5 (최근 30일)
Martin
Martin 2021년 5월 28일
댓글: Walter Roberson 2023년 1월 10일
I got this strange time format: my str ='Fri May 28 18:15:46 +0000 2021'.
I would be very happy if I could get it down to '28-May-2021 18:15:46'.
Tried messing with datetime(), but with no luck
Thank in advance

채택된 답변

Steven Lord
Steven Lord 2021년 5월 28일
str ='Fri May 28 18:15:46 +0000 2021'
str = 'Fri May 28 18:15:46 +0000 2021'
inputFormat = 'eee MMM d H:mm:ss xx yyyy'
inputFormat = 'eee MMM d H:mm:ss xx yyyy'
dt = datetime(str, 'InputFormat', inputFormat, 'TimeZone', 'UTC')
dt = datetime
28-May-2021 18:15:46
I used the information in the description of the Format property on the documentation page for the datetime function to generate inputFormat. Most of the identifiers were in the "All Date and Time Formats" table. I wasn't sure whether you wanted to use Z, xx, or xxxx. When I tried just using the InputFormat name-value pair input MATLAB threw an error that indicated I needed to specify a TimeZone as well.

추가 답변 (1개)

Walter Roberson
Walter Roberson 2021년 5월 28일
str ='Fri May 28 18:15:46 +0000 2021'
str = 'Fri May 28 18:15:46 +0000 2021'
datetime(str, 'inputformat', 'eee MMM dd HH:mm:ss Z yyyy','timezone','utc')
ans = datetime
28-May-2021 18:15:46
  댓글 수: 2
Tota
Tota 2023년 1월 10일
i have millscond (gaze time stamp) but need convert to time hh:mm:ss
if can help
Walter Roberson
Walter Roberson 2023년 1월 10일
GazeTimestamp = [1535.81; 169225; 1614.36; 1254.72]
GazeTimestamp = 4×1
1.0e+05 * 0.0154 1.6923 0.0161 0.0125
D = seconds(GazeTimestamp ./ 1000);
D.Format = 'hh:mm:ss'
D = 4×1 duration array
00:00:01 00:02:49 00:00:01 00:00:01

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