Issue with sine graph

조회 수: 2 (최근 30일)
Kaylee Chavez
Kaylee Chavez 2021년 5월 22일
댓글: DGM 2021년 5월 23일
I am having some difficulty graphing a function using sine. I graph it and it is either a y =x type graph or just lines. If someone could provide some direction that would be great.
%Oblique Balance Script
figure('Name','Team A Graphs');
clf;
%%Weight Ratio
subplot(2,1,1)
t=[0:0.01:180]
r = sind(30 + t) ./ sind(30 - t);
plot(t, r);
area(t,r,'FaceColor',[.8,.9,1.0]);
%Weight Graph
title('Weight ratio')
xlabel('Angle change')
ylabel('Ratio')

답변 (1개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2021년 5월 22일
Hi,
If you're trying to plot the weight ratio explained in your previous post, that has to be up to 30 degrees.
Thus, you'd need to make some corrections in your code while selecting the range t values, e.g.:
...
t=0:.25:29;
...
Note that at t=30, y goes to inf.
Good luck.
  댓글 수: 1
DGM
DGM 2021년 5월 23일
For emphasis:
t=[0:0.01:180];
r = sind(30 + t) ./ sind(30 - t); % the denominator goes to zero.
plot(t, r);
area(t,r,'FaceColor',[.8,.9,1.0]);
ylim([-100 100]) % so explicitly limit y limits
I have no idea what this plot means conceptually, but that's why it looks like it does.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Graph and Network Algorithms에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by