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Symbolic SVD for square matrix

조회 수: 3(최근 30일)
Diego Rodríguez
Diego Rodríguez 2021년 5월 17일
댓글: Diego Rodríguez 2021년 5월 18일
Hi everyone,
I'm developing a generic study of singular value decomposition (SVD) for square symetric matrix. The aim is to obtain generic functions where to substitute the generic coefficients of the matrix for functions to solve whether they became 0 or not. My code for the generic SVD computation is the following one:
M = sym('M', [6 6]);
M(2,1) = M(1,2);
M(3,1) = M(1,3);
M(3,2) = M(2,3);
M(4,1) = M(1,4);
M(4,2) = M(2,4);
M(4,3) = M(3,4);
M(5,1) = M(1,5);
M(5,2) = M(2,5);
M(5,3) = M(3,5);
M(5,4) = M(4,5);
M(6,1) = M(1,6);
M(6,2) = M(2,6);
M(6,3) = M(3,6);
M(6,4) = M(4,6);
M(6,5) = M(5,6);
detM = det(M);
disp('Determinant already computed... ');
svdM = svd(M);
The problem is that everything works fine when you describe a symbolic matrix with size smaller than 5 x 5. However, when I tested it with 6 x 6 or bigger matrixes, it seems that Matlab cannot handle the computation and never shows a results. I'll leave the code running for 5 days without obtaining any result, which is pretty strange because with 5x5 or below matrixes, it computes them perfectly under 2 minutes of time. Thus, I am wondering if this issue is some sort of limitation of symbolic computation of SVD? How could I compute efficiently the SVD for large symbolic matrixes?
Thanks in advance for any possible help!


Christine Tobler
Christine Tobler 2021년 5월 17일
The computation of the SVD in symbolic mathematics involves the solving of a polynomial equation of degree given by the size of the input matrix. However, there is no closed-form solution in general for polynomial equations that are quintic or higher:
So the problem is not solvable.
  댓글 수: 3
Diego Rodríguez
Diego Rodríguez 2021년 5월 18일
Thank you so much for your answers. I'll figure out another way to do what I'm aiming to. That's true, the complexity grows too quickly when working with symbolic matrixes. I'll close this issue since it has no clear solution.

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