How to match matrix dimensions?

I am making a silly mistake, I am sure, in matching my matrix dimensions. If anyone can spot what I am doing wrong it would be appreciated.

Here is the code to calculate 6 simultaneous equations with 6 unknown variables:

function F = correlation3; 

X = [259, 266, 298, 322, 310, 339, 398];               
Y = [64.6, 65.48, 65.28, 65.66, 65.86, 65.83, 65.37];  
Z = [-42, -35.8, -24.8, -16, -19.7, -9.5 -1];           

X2  =  X  .* X;          %Used to simplify the matrix notation within 
X3  =  X2 .* X;          %the while loop.
Y2  =  Y  .* Y;
Y3  =  Y2 .* Y;
Z2  =  Z  .* Z;

       q = [X3 .* X,   X3,       X2 .* Y2,   X2 .* Y,   X3 .* Y,    X2;
            X3,        X2,       X .* Y2,    Y.* X,     X2 .* Y,    X;
            X2 .* Y2,  X .* Y2,  Y3 .* Y,    Y3,        Y3 .* X,    Y2;
            X2 .* Y,   X .* Y,   Y3,         Y2,        X .* Y2,    Y;
            X3 .* Y,   X2 .* Y,  Y3 .* X,    X .* Y2,   X2 .* Y2,   Y .* X;
            X2,        X,        Y2,         Y,         Y .* X,     1];

        p = [X2.*Z; X.*Z; Y2.*Z; Y.*Z; Y.*Z; Z2];

        A, B, C, D, E, F=q\p

end

The error I am presented with is:

"Error using vertcat Dimensions of matrices being concatenated are not consistent.

Error in correlation3 (line 13) q = [X3 .* X, X3, X2 .* Y2, X2 .* Y, X3 .* Y, X2;"

Thanks

[Jackie]

Having updated the code with the correction bellow I have a 7 by 42 matrix being produced. Surely this matrix should be a 6 by 1? Seeing as:

"Solution, specified as a vector, full matrix, or sparse matrix. If A is an m-by-n matrix and B is an m-by-p matrix, then x is an n-by-p matrix, including the case when p==1."

And I am starting with a 6 by 6 and a 6 by 1 therefore according to the explanation it should be a 6 by 1?

[Youssef Khmou]

yes the solution x should be [m,p=1],

Answer 1

[Youssef Khmou]

hi Jackie,

The mistake is obvious, its the last component 1, replace it with

 ones(1,length(X))

[Jackie]

Thank you! Not something I would have found myself but something to remember for the future.

[Youssef Khmou]

ok, you can still use your first try but with cells

 >> doc cell