I'm running a script with a index containing:
t{1} = Location1;
t{2} = Location2;
t{3} = Location3;
tt{1} = "Location1";
tt{2} = "Location2";
tt{3} = "Location3";
t's are tables. Now the actual script does e.g. this:
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a_tt{n}(x) = b_tt{n}(x) / t{n}.var2(x);
if t{n}.var2(x) == 0
a_tt{n}(x) = 0;
end
As can be seen above I am trying to get a_Location1 and b_Location2 - but it does not work that way. Is there a smooth way to get a_location1/2/3 and b_location1/2/3 using the index?
It's for a lot of lines in the script, so some way without doing it by hand, would be nice!
Thanks for your help!

댓글 수: 2

one solution that would work is:
str1 = "a_" + tt{n};
str2 = "b_" + tt{n};
But as stated above, I have lots of those variables, is there maybe a better way?
Rik
Rik 2021년 5월 12일
Why do you want numbered variables? You shouldn't store data in a variable name.

댓글을 달려면 로그인하십시오.

 채택된 답변

Jan
Jan 2021년 5월 12일

0 개 추천

Do not create variables names dynamically. This would store information in the names, where it is hard to access. Use the values of the variables instead.
You can use dynamic field names of structs:
a = struct()
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a.(tt{n})(x) = b_tt{n}(x) / t{n}.var2(x);
elseif t{n}.var2(x) == 0
a.(tt{n})(x) = 0;
end
end

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Matrix Indexing에 대해 자세히 알아보기

제품

릴리스

R2021a

질문:

2021년 5월 12일

댓글:

2021년 5월 13일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by