find all sequences between delimiters in an array

Given a sequence of numbers and a start and an end delimiters, how to find the index (start and end) of all possible sequence of numbers between delimiters (sequences can be of any length). Example:

v = [1 1 0 2 0 2 1 2 1 1 1 0 2 1 2 0 0 1 1 1 1 1 1 2 1 0 ]

A list of non-overalpping sequences and their start and end index that begin with 2 and end with 0 would be:

[2 0]

[2 1 2 1 1 1 0]

[2 1 2 0]

[2 1 0]

I feel like this could be solved using regular expression.

[Stephen23]

If the numbers are always positive integers <10 then this is easy. If the values can be >=10 or if you want to consider non-integer values then the task requires a bit more thought. What restrictions/limits do you have on the number values?

[Kais]

I can live with the range of numbers in the example. Three values!

Answer 1

[Stephen23]

v = [1,1,0,2,0,2,1,2,1,1,1,0,2,1,2,0,0,1,1,1,1,1,1,2,1,0];
[begIdx,endIdx,~,match] = regexp(sprintf('%d',v),'2.*?0')

begIdx = 1×4

4 6 13 24

endIdx = 1×4

5 12 16 26

match = 1×4 cell array
    {'20'}    {'2121110'}    {'2120'}    {'210'}

Answer 2

[Jonas]

you could convert the array to a string or char array and then use extractBetween() which does what you want

[Kais]

Thanks! it does not unfortunately. It will return overlapping sequences and it does not return indices.