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# Plot discrete fourier transform of a sine wave

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Cynthia Lucy 2021년 5월 10일
댓글: Star Strider 2021년 5월 10일
Hi, I want to plot the sampled signal in frequency domain which means I need to use the discrete fourier transform, right? But when I run the code below I only get the display of sampled signal in discrete time domain and an error saying vector lengths must match came out on the command window. What does this mean? And what should be fixed? Please help me.
%chap1-38a
f = 6000;
fs = 16000;
w = 2*pi*(f/fs);
n = 0:50;
y = sin(w.*n);
subplot(2,1,1);
stem(n,y);
f = -fs/2:fs/(N-1):fs/2;
z = fftshift(fft(x));
subplot(2,1,2);
plot(f,abs(z));
The display when I run the code. 댓글을 달려면 로그인하십시오.

### 채택된 답변

Star Strider 2021년 5월 10일
Try this —
f = 6000;
fs = 16000;
w = 2*pi*(f/fs);
N = 50;
n = 0:N;
y = sin(w.*n);
subplot(2,1,1);
stem(n,y);
f = -fs/2:fs/(N):fs/2;
z = fftshift(fft(y));
subplot(2,1,2);
plot(f,abs(z)); I will let you discover the changes I made that are necessary to make it run!
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Star Strider 2021년 5월 10일
As always, my pleasure!

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