deleting part of a string

I have a string that I only want part of how do I get rid of the part I do not need.

for example:

original          new
dogcat_1_12334 ==>dogcat
dogcat_2_13342 ==>dogcat
dogcat_3_13442 ==>dogcat

Answer 1

[Jan]

s = 'dogcat_1_12334';
t = strtok(s, '_');

[arvind ramasamy]

I make a serial communication with an arduino and get the data of accelerometer mag and gyro values my data comes in as a string. 's' is the object i created for serial communication

data =fscanf(s,%s) % gives me the data from the arduino

i want my vector size to be 500. so when I run it in for loop

for i= 1:50

data =fscanf(s,'%s');

end

my output is: data = initializationsuccesful!

data = ax:123ay:23az:1234gx:23gy:50gz:43mx:23my:123mz:234

and goes on.

I use,

A_x(:,i) = str2num(data(:,4:8))

to get my vector. but since 'initializationsuccessful!' is not a number i am unable to form my vector. so how can I do it ???? this is my question

Answer 2

[Evan]

Here's another answer, just in case the characters you want to keep don't fall in sequential order. If they don't, regexp with a "match" argument will split them up into separate cells. regexprep however, will just remove the unwanted parts.

ex1 = 'dogcat_1_12334'
ex2 = 'dog_1_12334_cat'

>> regexprep(ex1,'[^a-z]','')
ans =
dogcat

>> regexprep(ex2,'[^a-z]','')
ans =
dogcat

To modify this for more general cases, just change the string argument '[^a-z]'. Put any characters than you want to keep from being removed in the brackets []. The carat ^ operator specifies that "everything but" what is present in the brackets is modified to the second string argument, ''. Since '' is blank, that means anything not in the [^] will be removed.

Answer 3

[Azzi Abdelmalek]

original='dogcat_1_12334'
new=regexp(str,'[a-z]+','match']

[Azzi Abdelmalek]

in case you have numbers and characters

   new=regexp(str,'[a-z0-9]+','match','once')