Getting error while deleting every row of the matrix M that contains the variable x
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I'm trying to write a function N = Deletevar(x,M) that returns a matrix N by deleting every row of the matrix M that contains the variable x.
My code is :
function N = Delete_var(x,M)
N = [];
[a,b] = size(M);
for i = 1:a
for j = 1:b
if M(i,j)== x
M(i,:)=[];
N = M;
end
end
end
end
However when i call Delete_var(3,[1,2,3;3,4,5;7,8,9]), I get:
Index in position 1 exceeds array bounds (must not exceed 2).
Error in Delete_var (line 9)
if M(i,j)== x
Why is that? How to solve the problem? Please help!
댓글 수: 2
David Fletcher
2021년 5월 1일
편집: David Fletcher
2021년 5월 1일
The inherent problem you have with the logic of your code is that you are basing the for loops on the starting size of the array (M). Consider what happens when you delete a row in M - the row dimension becomes smaller, but this is not reflected in the for loop which is still based on the starting size of the array. The code will always ultimately throw an error (unless no rows are deleted) since there will be a mismatch between the starting size of M and its size after rows are deleted.
채택된 답변
per isakson
2021년 5월 1일
편집: per isakson
2021년 5월 1일
The trick is to iterate in reverse order, i.e a:-1:1 instead of 1:a. Try this
%%
M = magic(5);
x = 13;
N = Delete_var(x,M)
%%
function N = Delete_var(x,M)
N = [];
[a,b] = size(M);
for i = a:-1:1
for j = b:-1:1
if M(i,j)== x
M(i,:)=[];
N = M;
end
end
end
end
추가 답변 (1개)
Turlough Hughes
2021년 5월 1일
No need for any loops. Here's an example of data to work with
M = randi(10,[10 3]); % sample data
x = 3; % delete rows with this value
You can delete any rows in M containing x as follows:
M(any(M==x,2),:)=[];
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