compare two vectors then insert missing element

조회 수: 3 (최근 30일)
james sinos
james sinos 2021년 4월 29일
답변: Stephen23 2021년 4월 29일
i have a matrix :
A=[ 1.000 0.5860 0.01403
2.500 0.7395 0.01277
3.500 0.8450 0.01146
4.000 0.8967 0.01173
4.500 0.9476 0.01215
5.000 0.9962 0.01280
6.000 1.0973 0.01367
6.500 1.1398 0.01457
7.000 1.1889 0.01515
8.000 1.2574 0.01915
8.500 1.2816 0.02234
9.500 1.3300 0.02731
10.500 1.3267 0.03649 ]
for the first column let say its
B=[ 1.000
1.500
2.000
2.500
3.500
4.000
4.500
5.000
5.500
6.000
6.500
7.000
7.500
8.000
8.500
9.000
9.500
10.000
10.500]
i want to compare A(:1) with b then insert missing rows to make A(:,1) = b , then perform interpolation for A(:,2) and A(:,3) new rows
thanks
  댓글 수: 1
Chunru
Chunru 2021년 4월 29일
Bq = sort(union(B, A(:,1))); % the query points are from B and A(:,1)
C = interp1(A(:, 1), A(:, 2:end), Bq); % Interpolation
C = [Bq C]; % The result

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답변 (1개)

Stephen23
Stephen23 2021년 4월 29일
Simpler:
A=[ 1.000 0.5860 0.01403
2.500 0.7395 0.01277
3.500 0.8450 0.01146
4.000 0.8967 0.01173
4.500 0.9476 0.01215
5.000 0.9962 0.01280
6.000 1.0973 0.01367
6.500 1.1398 0.01457
7.000 1.1889 0.01515
8.000 1.2574 0.01915
8.500 1.2816 0.02234
9.500 1.3300 0.02731
10.500 1.3267 0.03649 ];
B = 1:0.5:10.5;
C = interp1(A(:,1),A,B(:))
C = 20×3
1.0000 0.5860 0.0140 1.5000 0.6372 0.0136 2.0000 0.6883 0.0132 2.5000 0.7395 0.0128 3.0000 0.7923 0.0121 3.5000 0.8450 0.0115 4.0000 0.8967 0.0117 4.5000 0.9476 0.0121 5.0000 0.9962 0.0128 5.5000 1.0467 0.0132

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