what is wrong with this code

조회 수: 12 (최근 30일)
JJ
JJ 2021년 4월 28일
답변: Image Analyst 2021년 4월 28일
figure
x=0:0.01:2;
plot(conc,x,'r-')
xlabel('distance from the source (m)')
ylabel('concentration (mol/l')
title('the concentration of a substance with distance from initial source')
Error using CES_StudentID_empty>conc
Too many output arguments.
Error in CES_StudentID_empty (line 48)
plot(conc,x,'r-')
  댓글 수: 3
Walter Roberson
Walter Roberson 2021년 4월 28일
We should suspect from the code and error that conc is not a variable, and is instead a function that is defined as not returning any output.
Image Analyst
Image Analyst 2021년 4월 28일
What is that? That's a script, not a function.

댓글을 달려면 로그인하십시오.

채택된 답변

Image Analyst
Image Analyst 2021년 4월 28일
Try this:
% Demo by Image Analyst.
clc; % Clear the command window.
fprintf('Beginning to run %s.m ...\n', mfilename);
close all; % Close all figures (except those of imtool.)
clearvars;
workspace; % Make sure the workspace panel is showing.
format short g;
format compact;
fontSize = 16;
t=86400;
v=10.^-5;
D=10.^-7;
x=0:0.01:2;
%Calcuate the concentration in ( mol/l)
conc = (1./sqrt(4 * pi * D * t)* exp(-1 * ((x - v * t) .^ 2 ./ 4 * D )));
plot(conc, x, 'r-', 'LineWidth', 3)
grid on;
xlabel('Distance from the source (m)', 'FontSize', fontSize)
ylabel('Concentration (mol/l', 'FontSize', fontSize)
title('The concentration of a substance with distance from initial source', 'FontSize', fontSize)
fprintf('Done running %s.m\n', mfilename);

추가 답변 (1개)

Walter Roberson
Walter Roberson 2021년 4월 28일
You currently have
t=86400;
v=10.^-5;
D=10.^-7;
x=0:0.01:2;
%Calcuate the concentration in ( mol/l)
conc=(1./sqrt(4 * pi * D * t)* exp(-1 * ((x - v * t) .^ 2 ./ 4 * D )));
stored in conc.m . Rename that file to calculate_conc.m . Then
figure
calculate_conc;
plot(conc,x,'r-')
xlabel('distance from the source (m)')
ylabel('concentration (mol/l')
title('the concentration of a substance with distance from initial source')

카테고리

Help CenterFile Exchange에서 MATLAB Report Generator에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by