Finding corresponding values between array

조회 수: 5 (최근 30일)
JaffaCakes
JaffaCakes 2021년 4월 28일
댓글: JaffaCakes 2021년 4월 28일
Hi, Suppose I have any matrix A(1,j) where j is columns
and t from 0:5:30
and for each value of t I have a corresponding j value
so e.g. t= 0 5 10 15 20 25 30
and j= 1 11 21 31..... corresponding to the t values.
How can I find an element within matrix A, corresponding to each of j values (columns)?
I've tried to do something like this so far,but it didnt work.
t= 0 5 10 15 20 25 30
j= 1 11 21 31.....
v=length(t)
for k=1:v
y=A(1,J(v))
end

채택된 답변

Steven Lord
Steven Lord 2021년 4월 28일
I'm not certain I understand your question. Let's take a concrete example. Can you tell us what the answer you'd want to receive for this example is and how you calculated that answer?
t = 0:5:30;
j = 1:10:61;
A = (1:61).^2;
Is it as simple as indexing?
y = A(1, j)
y = 1×7
1 121 441 961 1681 2601 3721
results = table(t.', j.', y.', j.'.^2, ...
'VariableNames', ["t", "j values", "y values", "j^2 to check"])
results = 7×4 table
t j values y values j^2 to check __ ________ ________ ____________ 0 1 1 1 5 11 121 121 10 21 441 441 15 31 961 961 20 41 1681 1681 25 51 2601 2601 30 61 3721 3721
  댓글 수: 2
JaffaCakes
JaffaCakes 2021년 4월 28일
편집: JaffaCakes 2021년 4월 28일
Hi, the problem is, I can't index like you've written because J is given by an equation (not as simple as the one i've shown here)
t=0:5:30
J=2*t+1 %j is given by an equation, would like to take these values of J and input into the matrix column
y=A(1,J) %gives an error saying, index exceeds matrix dimensions
JaffaCakes
JaffaCakes 2021년 4월 28일
Hi, nm I've sorted it out. Thanks for the help though

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Linear Algebra에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by