Function to create struct with parameters

조회 수: 5 (최근 30일)
Felix Müller
Felix Müller 2021년 4월 26일
댓글: Felix Müller 2021년 4월 27일
Currently I have a function with settings/parameters for my program, where all parameters are written into a struct like "inp.month = 7;" so that I can pass the struct "inp" to functions afterwards. Is it possible to have all the assignments in the function without the struct, eg "month = 7;" and at the end somehow get 'all variables in this function' into the struct "inp". Something like "inp = <gather all variables assigned in this function>", and then have the struct be the output. It would add readability in my opinion and also I thought this to be easy, but didn't find a good solution yet and thought I'd ask here.
Cheers
Felix
  댓글 수: 5
Bruno Luong
Bruno Luong 2021년 4월 27일
This request is interesting only for lazy programmers who wants to make a quick and dirty code.
Just create a struct with the list of variables that you control explicitly.
Felix Müller
Felix Müller 2021년 4월 27일
Well, that might not be so obvious before thinking about it, eh?

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채택된 답변

Jeff Miller
Jeff Miller 2021년 4월 26일
Maybe you would like something like this?
month = 1;
year = 1951;
day = 11;
inp = CreateStruct(month,day,year)
function outstruc = CreateStruct(varargin)
% Create a structure with the input variables as fields.
outstruc = struct;
for iField=1:numel(varargin)
sfName = inputname(iField);
outstruc.(sfName) = varargin{iField};
end
end
  댓글 수: 2
Felix Müller
Felix Müller 2021년 4월 27일
Thanks, that does look interesting. Do you think there are any drawbacks or weird errors that could pop up while using this?
Stephen23
Stephen23 2021년 4월 27일
편집: Stephen23 2021년 4월 27일
"Do you think there are any drawbacks...?"
Slower code: "Avoid functions that query the state of MATLAB such as inputname, which, whos, exist(var), and dbstack. Run-time introspection is computationally expensive."

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추가 답변 (2개)

Walter Roberson
Walter Roberson 2021년 4월 26일
The following code is not recommended.. but it should work.
ZZ_filename = [tempname '.mat'];
save(ZZ_filename, '-struct', '-regexp', '^[^Z]', '^Z[^Z]');
inp = load(ZZ_filename);
delete(ZZ_filename);
If you already have variable names that begin with 'ZZ' then this code would have to be modified.
The purpose of the -regexp is to allow saving all of the variables except the over-head variable ZZ_filename .
  댓글 수: 3
Walter Roberson
Walter Roberson 2021년 4월 26일
Then you will need to write code that uses dynamic variable naming, which is not at all recommended.
Hint: who() returns names of variables.
Felix Müller
Felix Müller 2021년 4월 26일
Okay, thanks! I thought it might work without fiddling with the assignment of variables myself (eg with a function written exactly for this), but it might not.

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Bruno Luong
Bruno Luong 2021년 4월 27일
s = buildparams()
s = struct with fields:
a: 1 b: 2
function s = buildparams()
a = 1;
b = 2;
s = gathervars();
end
function s = gathervars()
vars = evalin('caller', 'whos');
for k=1:length(vars)
name = vars(k).name;
s.(name) = evalin('caller', name);
end
end

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