using forecast in combination with nlarx gives an error

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Leon 2021년 4월 22일
답변: Stefanie Schwarz 2021년 4월 27일
When I try to use the forecast function in combination with a nlarx I get the following error: Unable to use a value of type idnlarx as an index
When I train the model and use the compare function everything works fine with no error message.
I am using the following code:
z = iddata(y_output, x_input, 1);
sys1 = nlarx(z(1:300),[15 15 1]);
forecast = 6;
figure(); compare(z(1:800), sys1, forecast);
Y_Pred = forecast(sys1, z(1:500), 6, z.u(501:506));
Can anyone help?
Thx in advance. Best regards

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Stefanie Schwarz
Stefanie Schwarz 2021년 4월 27일
The error message is caused by the variable "forecast=6" in your code that shadows the "forecast" function. Please rename the variable to something else.
For more info, see also:

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