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How do I create function that is defined by itself?

조회 수: 3 (최근 30일)
Hjalmar Stenberg
Hjalmar Stenberg 2021년 4월 22일
답변: Pratyush Roy 2021년 4월 27일
I need help creating this function. I have defined x(t) as
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3));
The end result should look like this

답변 (1개)

Pratyush Roy
Pratyush Roy 2021년 4월 27일
Hi,
As per the equations mentioned above, the function is a periodic one with a period of 4. You can refer to code snippet below to generate a periodic function:
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3))
duration = T;
t = 0:0.5:T; %Time interval is chosen as 0.5 in this case, user can change this value.
y = x(mod(t,4));%Period of 4
plot(t,y)
Hope this helps!

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