How do I create function that is defined by itself?

조회 수: 2 (최근 30일)
Hjalmar Stenberg
Hjalmar Stenberg 2021년 4월 22일
답변: Pratyush Roy 2021년 4월 27일
I need help creating this function. I have defined x(t) as
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3));
The end result should look like this

답변 (1개)

Pratyush Roy
Pratyush Roy 2021년 4월 27일
Hi,
As per the equations mentioned above, the function is a periodic one with a period of 4. You can refer to code snippet below to generate a periodic function:
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3))
duration = T;
t = 0:0.5:T; %Time interval is chosen as 0.5 in this case, user can change this value.
y = x(mod(t,4));%Period of 4
plot(t,y)
Hope this helps!

카테고리

Help CenterFile Exchange에서 MATLAB에 대해 자세히 알아보기

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by