Trouble solving ODE equations

조회 수: 1 (최근 30일)
Pr0t0nZ
Pr0t0nZ 2021년 4월 11일
댓글: Rena Berman 2021년 5월 6일
I am trying to solve these differential equations in order to plot graphs, however, when running the code I am receiving multiple errors but I'm unsure why as I can't see why the code is not running smoothly? I'm looking for some insight on why this might be happening and how I can solve the problem?
Equations and Parameter values:
function dydt = Dunster(t,y)
%Parameters and their values%
K1a = 20;
Y1a = 1;
K1b = 0.25;
K2a = 14;
K2am = 72;
K2b = 2.6;
K2bm = 10;
K2c = 24;
K2cm = 20;
K3a = 10;
K3b = 0.05;
K3c = 24;
K3cm = 20;
K4a = 2.3;
K4am = 58;
K4b = 2000;
K4bm = 210;
K4c = 1.3;
K5a = 0.0014;
K5b = 0.35;
K6 = 2000;
K6m = 2000;
Kx = 50;
Kb = 0.01;
Lb = 1;
Lx = 1;
Bxva = 0;
H = K1a*Y1a*exp(-Y1a*t);
bl = 0.5*((Kb+Lb+Bxva)-sqrt((Kb+Lb+Bxva)^2 - 4*Lb*Bxva));
%Equation 1%
%Generation and inactivation of factor Xa%
F1= y(1);
%y(1)= -K6*F1;
% Factor I
%Equation 2%
F5=y(2);
%y(2)=(-K2a*F2a*F5)/(F5+K2am(1+F1/K6m) - ((K2b*F10a*F5)/F5+K2bm(1+F2/K4am)));
%Equation 3%
F2=y(3);
%y(3)= ((-K4a*F1*F2)/F2+K4am(1+F5/K2bm))-((K4b*b1*F2)/(F2+K4bm));
%Equation 4%
C=y(4);
%y(4)= (-K5a*C);
%Equation 5%
F10a=y(5);
%y(5)= H +(K3c*Ca*Bxva)/(Bxva+K3cm) - K1b*F10a - K3a*F10a*F5a;
%Equation 6%
F5a=y(6);
%y(6)= (K2a*F2a*F5)/(F5+K2am(1+F1/K6m)) + (K2b*F10a*F5a)/(F5+K2bm(1+F1/K4am))+ K3b*Bxva - (K2c*Ca*F5a)/(F5a+K2am) - K3a*F10a*F5a;
%Equation 7%
Bxva=y(7);
%y(7)= K3a*F10a*F5a - K3b*Bxva - (K3c*Ca*Bxva)/(Bxva+K3cm);
%Equation 8%
F2a=y(8);
%y(8)= (K4a*F1*F2)/(F2+K4am(1+F5/K2bm)) + (K4b*BF2)/(F2+K4bm) - K4c*F2a;
%Equation 9%
Ca=y(9);
%y(9)= K5a*C - K5b*Ca;
%Equation 10%
F10i=y(10);
%y(10)= K1b*F10a + K3b*Bxva;
%Equation 11%
F5i=y(11);
%y(11) = (K2c*Ca*F5a)/(F5a+K2cm) + (K3c*Ca*Bxva/(Bxva+K3cm));
%Equation 12%
F2i=y(12);
%y(12) = K4c*F2a;
%Equation 13%
Ci=y(13);
%y(13) = K5b*Ca;
%Equation 14%
F1a=y(14);
%y(14) = K6*F1;
dydt=[
-K6*F1; % d F1 / dt
((-K2a*F2a*F5)/(F5+K2am*(1+F1/K6m)) - ((K2b*F10a*F5)/F5+K2bm*(1+F2/K4am))); % d F5 / dt
((-K4a*F1*F2)/(F2+K4am*(1+F5/K2bm))-((K4b*bl*F2)/(F2+K4bm))); % d F2 / dt
-K5a*C; % d C / dt
H+(K3c*Ca*Bxva)/(Bxva+K3cm) - K1b*F10a - K3a*F10a*F5a ;
% d F10a / dt
(K2a*F2a*F5)/(F5+K2am(1+F1/K6m)) + (K2b*F10a*F5a)/(F5+K2bm(1+F1/K4am))
+ K3b*Bxva - (K2c*Ca*F5a)/(F5a+K2am) - K3a*F10a*F5a; % d F5a / dt
K3a*F10a*F5a - K3b*Bxva - (K3c*Ca*Bxva)/(Bxva+K3cm); % d Bxva / dt
(K4a*F1*F2)/(F2+K4am(1+F5/K2bm)) + (K4b*BF2)/(F2+K4bm) - K4c*F2a ;
% d F2a / dt
K5a*C - K5b*Ca ; % d Ca / dt
K1b*F10a + K3b*Bxva ; % d F10i / dt
((K2c*Ca*F5a)/(F5a+K2cm) + (K3c*Ca*Bxva/(Bxva+K3cm))) ; % d F5i / dt
K4c*F2a ; % d F2i / dt
K5b*Ca ; % d Ci / dt
K6*F1 ; % d F1a / dt
];
end
Running Part of the Code:
tspan=[0 60];
F1=10000;
F5=30;
F2=1000;
C=100;
F10a=0;
F5a=0;
Bxva=0;
F2a=0;
Ca=0;
F10i=0;
F5i=0;
F2i=0;
Ci=0;
F1a=0;
y0=[F1;F5;F2;C;F10a;F5a;Bxva;F2a;Ca;F10i;F5i;F2i;Ci;F1a];
[t,y]=ode45(@Dunster, tspan, y0);%,[], pars);
plot(t/60, y(:,14)*1000, "r")
xlabel("Time [Min]")
ylabel("Concentration [nM]")
  댓글 수: 1
Rena Berman
Rena Berman 2021년 5월 6일
(Answers Dev) Restored edit

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답변 (1개)

Star Strider
Star Strider 2021년 4월 11일
There were several missing multiplication operators, and a reference to ‘BF2’ that I corrected to ‘F2’, since there is no ‘B’ that I can find, so no missing multiplication operator there. With those edits, and concatenating an additional 0 to ‘y0’ to make its length equal to the number of differential equations, this runs without error:
function dydt = Dunster(t,y)
%Parameters and their values%
K1a = 20;
Y1a = 1;
K1b = 0.25;
K2a = 14;
K2am = 72;
K2b = 2.6;
K2bm = 10;
K2c = 24;
K2cm = 20;
K3a = 10;
K3b = 0.05;
K3c = 24;
K3cm = 20;
K4a = 2.3;
K4am = 58;
K4b = 2000;
K4bm = 210;
K4c = 1.3;
K5a = 0.0014;
K5b = 0.35;
K6 = 2000;
K6m = 2000;
Kx = 50;
Kb = 0.01;
Lb = 1;
Lx = 1;
Bxva = 0;
H = K1a*Y1a*exp(-Y1a*t);
bl = 0.5*((Kb+Lb+Bxva)-sqrt((Kb+Lb+Bxva)^2 - 4*Lb*Bxva));
%Equation 1%
%Generation and inactivation of factor Xa%
F1= y(1);
%y(1)= -K6*F1;
% Factor I
%Equation 2%
F5=y(2);
%y(2)=(-K2a*F2a*F5)/(F5+K2am(1+F1/K6m) - ((K2b*F10a*F5)/F5+K2bm(1+F2/K4am)));
%Equation 3%
F2=y(3);
%y(3)= ((-K4a*F1*F2)/F2+K4am(1+F5/K2bm))-((K4b*b1*F2)/(F2+K4bm));
%Equation 4%
C=y(4);
%y(4)= (-K5a*C);
%Equation 5%
F10a=y(5);
%y(5)= H +(K3c*Ca*Bxva)/(Bxva+K3cm) - K1b*F10a - K3a*F10a*F5a;
%Equation 6%
F5a=y(6);
%y(6)= (K2a*F2a*F5)/(F5+K2am(1+F1/K6m)) + (K2b*F10a*F5a)/(F5+K2bm(1+F1/K4am))+ K3b*Bxva - (K2c*Ca*F5a)/(F5a+K2am) - K3a*F10a*F5a;
%Equation 7%
Bxva=y(7);
%y(7)= K3a*F10a*F5a - K3b*Bxva - (K3c*Ca*Bxva)/(Bxva+K3cm);
%Equation 8%
F2a=y(8);
%y(8)= (K4a*F1*F2)/(F2+K4am(1+F5/K2bm)) + (K4b*BF2)/(F2+K4bm) - K4c*F2a;
%Equation 9%
Ca=y(9);
%y(9)= K5a*C - K5b*Ca;
%Equation 10%
F10i=y(10);
%y(10)= K1b*F10a + K3b*Bxva;
%Equation 11%
F5i=y(11);
%y(11) = (K2c*Ca*F5a)/(F5a+K2cm) + (K3c*Ca*Bxva/(Bxva+K3cm));
%Equation 12%
F2i=y(12);
%y(12) = K4c*F2a;
%Equation 13%
Ci=y(13);
%y(13) = K5b*Ca;
%Equation 14%
F1a=y(14);
%y(14) = K6*F1;
dydt=[-K6*F1; % d F1 / dt
((-K2a*F2a*F5)/(F5+K2am*(1+F1/K6m)) - ((K2b*F10a*F5)/F5+K2bm*(1+F2/K4am))); % d F5 / dt
((-K4a*F1*F2)/(F2+K4am*(1+F5/K2bm))-((K4b*bl*F2)/(F2+K4bm))); % d F2 / dt
-K5a*C; % d C / dt
H+(K3c*Ca*Bxva)/(Bxva+K3cm) - K1b*F10a - K3a*F10a*F5a ;
% d F10a / dt
(K2a*F2a*F5)/(F5+K2am*(1+F1/K6m)) + (K2b*F10a*F5a)/(F5+K2bm*(1+F1/K4am))
+ K3b*Bxva - (K2c*Ca*F5a)/(F5a+K2am) - K3a*F10a*F5a; % d F5a / dt
K3a*F10a*F5a - K3b*Bxva - (K3c*Ca*Bxva)/(Bxva+K3cm); % d Bxva / dt
(K4a*F1*F2)/(F2+K4am*(1+F5/K2bm)) + (K4b*F2)/(F2+K4bm) - K4c*F2a ;
% d F2a / dt
K5a*C - K5b*Ca ; % d Ca / dt
K1b*F10a + K3b*Bxva ; % d F10i / dt
((K2c*Ca*F5a)/(F5a+K2cm) + (K3c*Ca*Bxva/(Bxva+K3cm))) ; % d F5i / dt
K4c*F2a ; % d F2i / dt
K5b*Ca ; % d Ci / dt
K6*F1 ; % d F1a / dt
];
end
% % Running Part of the Code:
tspan=[0 60];
F1=10000;
F5=30;
F2=1000;
C=100;
F10a=0;
F5a=0;
Bxva=0;
F2a=0;
Ca=0;
F10i=0;
F5i=0;
F2i=0;
Ci=0;
F1a=0;
y0=[F1;F5;F2;C;F10a;F5a;Bxva;F2a;Ca;F10i;F5i;F2i;Ci;F1a;0];
[t,y]=ode45(@Dunster, tspan, y0);%,[], pars);
plot(t/60, y(:,14)*1000, "r")
xlabel("Time [Min]")
ylabel("Concentration [nM]")
.
  댓글 수: 6
Pr0t0nZ
Pr0t0nZ 2021년 4월 11일

Hi,
I just wanted to say a massive thank you for all your help you have given me, honestly I can't stress enough how long i've been trying to sort this problem with no results and now my code is fully working and producing graphs!
So once again, thank you so much for all your help!
Cheers,
Jack

Star Strider
Star Strider 2021년 4월 11일
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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