How do i reconstruct a matrix???
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I have a matrix 2000x3 like this:
1 1 6
1 2 8
1 3 15
....
2 1 10
2 2 20
2 3 13
....
3 1 12
3 2 18
3 3 14
...
...
and i want to reconstruct like this:
1 1 6
1 2 8
1 3 15
....
2 3 13
2 2 20
2 1 10
....
3 1 12
3 2 18
3 3 14
...
...
Please help me..
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Image Analyst
2013년 6월 24일
편집: Image Analyst
2013년 6월 24일
The middle group has the second column flipped. But that's not enough to figure out what needs to be done in general. And what does this have to do with Image Processing, like the tag says?
채택된 답변
Andrei Bobrov
2013년 6월 25일
a - your array
a1 = a;
n = unique(a(:,1));
for jj = 1:numel(n)
if rem(n(jj),2) == 0
t = a1(:,1) == n(jj);
a1(t,:) = flipud(a1(t,:));
end
end
추가 답변 (2개)
Evan
2013년 6월 24일
M(:,:,2) = flipud(M(:,:,2))
As an example:
M = rand(3,3,3); %random example 3d matrix
M(:,:,2) = flipud(M(:,:,2));
댓글 수: 1
Evan
2013년 6월 26일
In light of George's update in the below comment, this code does not do what he is asking for. http://www.mathworks.com/matlabcentral/answers/79846#comment_156778
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