How to build a table within an if loop without preallocation

I'm having trouble building this table in my code. Currently it just displays the last value that was calculated rather than creating a table with all the values calculated. I have seen a lot of answers with for loops but none with if. Is there something I am missing? I even get the warning on T that it changes size every iteration, however, it doesn't seem to actually do that.

% Safety Factors
SFy = 1.25; % Yield
SFu = 1.50; % Ultimate
SFb = 2.0; % Stability

% ____ Material Properties
E = 31182; % (ksi) Modulus of Elasticity
Sy = 91.5; % (ksi) Yield Strength
Su = 112; % (ksi) Ultimate Strength

D = 0.25; % (in) Initial Outside Diameter Value
d = 0.001; % (in) Initial Inside Diameter Value
L = 36; % (in) Length of Bar
P = 3; % (ksi) Applied Axial Force

j = 1; % Book-keeping

while D <= 2 && d <= 0.249
    I = pi*(D^4-d^4)/64; % (in^4) Moment of Inertia
    Pcrt = (pi^2*E*I)/(L^2); % Calculating Pcr
    SFbt = Pcrt/P;
    
    if SFbt >= SFb
        A = pi*(D^2-d^2)/4; % (in^2) Area Value
        s = P/A; % (ksi) Axial Stress = Force/Area
        SFyt = Sy/s; % Calculating Safety Factor Yield
        SFut = Su/s; % Calculating Saftey Factor Ultimate

        T = table(); % Storage Table
        tempTable = table();

        if SFyt >= SFy && SFut >= SFu % Checking for Validity
            tempTable.D = D;
            tempTable.d = d;
            tempTable.A = A;
            tempTable.s = s;
            tempTable.Pcrt = Pcrt;
            tempTable.SFut = SFut;
            tempTable.SFyt = SFyt;
            tempTable.SFbt = SFbt;
            T = [T; tempTable];
        end
    end
    if D >= 1.989 % Running Through Possibilities
        d = d + 0.001;
        D = 0.25;
    end
    
    D = D + 0.01;
    j = j+1;
end

Answer 1

[David Fletcher]

Doubtless, you will kick yourself - but put your main table declaration outside the loop, or you'll be overwriting the old main table and everything you put in it with a new table on every iteration.

% Safety Factors
        SFy = 1.25; % Yield
        SFu = 1.50; % Ultimate
        SFb = 2.0; % Stability
        % ____ Material Properties
        E = 31182; % (ksi) Modulus of Elasticity
        Sy = 91.5; % (ksi) Yield Strength
        Su = 112; % (ksi) Ultimate Strength
        D = 0.25; % (in) Initial Outside Diameter Value
        d = 0.001; % (in) Initial Inside Diameter Value
        L = 36; % (in) Length of Bar
        P = 3; % (ksi) Applied Axial Force
        j = 1; % Book-keeping
        T = table(); % Storage Table <----------------------- PUT TABLE DECLARATION BEFORE TEH LOOP
        while D <= 2 && d <= 0.249
            I = pi*(D^4-d^4)/64; % (in^4) Moment of Inertia
            Pcrt = (pi^2*E*I)/(L^2); % Calculating Pcr
            SFbt = Pcrt/P;
            
            if SFbt >= SFb
                A = pi*(D^2-d^2)/4; % (in^2) Area Value
                s = P/A; % (ksi) Axial Stress = Force/Area
                SFyt = Sy/s; % Calculating Safety Factor Yield
                SFut = Su/s; % Calculating Saftey Factor Ultimate
                % T = table(); <---------------------- THIS IS THE PROBLEM
                tempTable = table();
                if SFyt >= SFy && SFut >= SFu % Checking for Validity
                    tempTable.D = D;
                    tempTable.d = d;
                    tempTable.A = A;
                    tempTable.s = s;
                    tempTable.Pcrt = Pcrt;
                    tempTable.SFut = SFut;
                    tempTable.SFyt = SFyt;
                    tempTable.SFbt = SFbt;
                    T = [T; tempTable];
                end
            end
            if D >= 1.989 % Running Through Possibilities
                d = d + 0.001;
                D = 0.25;
            end
            
            D = D + 0.01;
            j = j+1;
        end

[Gavin Goddard]

Oh gosh, thank you.