Matlab problem conv function
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n3=0:110
u=1.*(n3>=0);
y=conv(u, h2);
subplot(212);
stem(0:length(y)-1, y);
xlabel('n');
ylabel('Convolutia liniara ya(n)=xa(n)\otimes h(n)');
Can someone explain why is conv used if i want a response at unit step of function h2?
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카테고리
도움말 센터 및 File Exchange에서 Correlation and Convolution에 대해 자세히 알아보기
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