I am trying to use below code to calculate and write into new variable but it's taking last value and giving same whole vector.
for k=1:3
for j = 22:24
%three values expected and write into A
A(k,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
end
end
output:
A = [0.5;0.5;0.5]

댓글 수: 5

hello
sure , you are doing 3 times the same operation, so it is no surprise that A contains always the same value.
what is the intention ? why the 2 loops ?
I want to keep each calculation value of "j" into A. If you see
A(k,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
% three results expected and write into A .
if i understood correctly then,
it is because your inner loop runs over j several times for each k value
hence in A the k position which you have given is overwritter for each j.
count = 1;
for k=1:3
for j = 22:24
%three values expected and write into A
A(count,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
count = count+1;
end
end
if this doesnt solves your query then please do explain your problem in other way as is it difficult to understand your current description of problem
It worked !
Thank you so much. I just don't need k=1:3 loop.
appreciated your help :)
Sajid Afaque
Sajid Afaque 2021년 4월 2일
편집: Sajid Afaque 2021년 4월 2일
Great that it worked. @Jeevan Kumar Bodaballa
if my comment helped you then please accept my answer, as my previous answer was in comment section

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Sajid Afaque
Sajid Afaque 2021년 4월 2일
if i understood correctly then,
it is because your inner loop runs over j several times for each k value
hence in A the k position which you have given is overwritter for each j.
count = 1;
for k=1:3
for j = 22:24
%three values expected and write into A
A(count,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
count = count+1;
end
end
if this doesnt solves your query then please do explain your problem in other way as is it difficult to understand your current description of problem

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