sprintf conflict in operations

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Opariuc Andrei
Opariuc Andrei 2021년 3월 24일
댓글: Star Strider 2021년 3월 24일
receiving 5 values for Mt2b while using sprintf for Pmax (i used to to get an exact value without variables) .if i remove sprintf from Pmax i'm receiving 1 value as needed .The question being how can fix my result for Mt2b without having to remove sprintf from Pmax ?
Fa=88050;
E=2.1*10^5;
R=200;
r0=1.11*((Fa*R)/E)^(1/3)
Pmax=sprintf('%.0f\n',0.39*((Fa*E^2)/R^2)^(1/3))
Mt2b=sprintf('%.0f\n',((pi^2)/8)*0.2*Pmax*r0^3)

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Star Strider
Star Strider 2021년 3월 24일
To use ‘Pmax’ in a calculation, it has to be turned back into a number.
Try this:
Mt2b=sprintf('%.0f\n',((pi^2)/8)*0.2*str2double(Pmax)*r0^3)
producing:
Mt2b =
'50709
'
.
  댓글 수: 2
Star Strider
Star Strider 2021년 3월 24일
As always, my pleasure!
The online documentation reference is str2double

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