필터 지우기
필터 지우기

One image 2 diferent colors ,

조회 수: 1 (최근 30일)
Biza Ferreira
Biza Ferreira 2013년 6월 5일
댓글: Image Analyst 2014년 4월 27일
I have one image with a circle, outside the circunference the color are black inside the circle the color before convert to grayscale, is gray, how can apply after normalize de image apply a mask who convert a the background in same color (gray). https://www.dropbox.com/sc/zfp80poi11m8q55/lnRX67BT4L exemple image A and B

채택된 답변

Image Analyst
Image Analyst 2013년 6월 5일
It looks like B was simply the convolution of A with a high pass filter, like the Laplacian or dog filter. Do you want to do that or you simply want the black surround to be gray?
  댓글 수: 2
roudabe
roudabe 2014년 4월 27일
Would you please let me now how can I use Laplacian high pass filter on images?
Image Analyst
Image Analyst 2014년 4월 27일
kernel = [-1,-1,-1;-1,8,-1;-1,-1,-1];
output = conv2(double(inputImage), kernel, 'same');
imshow(output, []);

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Biza Ferreira
Biza Ferreira 2013년 6월 5일
편집: Biza Ferreira 2013년 6월 5일
I Removing the background image was obtained by subtracting the original version of this image strongly smoothed (result of filtering with a filter medium sized relatively high). The intensities of the image resulting from the subtraction were subsequently reescaladas for the full range of image intensities (0-255).
if true
fontSize= 12;
A = imread('imagens/03_test.tif');
%B = rgb2gray(A);%original a P&B
ft_high=[0 -1/4 0; -1/4 2 -1/4; 0 -1/4 0];
h = fspecial('average', [5 5]);
filtered= imfilter(A,h,'replicate');
filtered1= imfilter(A,ft_high,'replicate');
Subtract=filtered-A;
Subtract1=A-filtered1;
B = rgb2gray(Subtract1);%original a P&B
J = imadjust(B);
figure;
subplot(2,2,1);
imshow(A),
title('Original Image Color', 'FontSize', fontSize);
subplot(2,2,2);
imshow(filtered);
title('Filter Image Median', 'FontSize', fontSize);
subplot(2,2,3);
imshow(filtered1);
title('Filter Image Median with High', 'FontSize', fontSize);
subplot(2,2,4);
imshow(Subtract);
end
  댓글 수: 1
Image Analyst
Image Analyst 2013년 6월 5일
So does this answer your question? If so, let's finish it off by marking it as the "Accepted" answer.

댓글을 달려면 로그인하십시오.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by