Stability of Transfer Function
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Hello,
I can't understand how to define the stability of a Transfer Function (Stable, Unstable or Marginally Stable)
- f(t) = 0, as t(s) = inf, then the system is Stable.
- f(t) = inf, as t(s) = inf, then the system is UnStable.
- f(t) ~= 0 or inf , as t(s) = inf, then the system is Marginally Stable.
I don't want to use the "isstable", because it only tells you if it is stable or not.
It doesn't inform you in case if it is Marginally Stable.

%%
clc;
clear all;
close all;
%% 3
%% 3.1
numA = [-7 2];
denA = [4 4];
GA = tf(numA,denA);
%% 3.2
numB = [4 -7];
denB = [2 2];
GB = tf(numB,denB);
%% 3.3
numC = [1 1];
denC = [4 -7 2];
GC = tf(numC,denC);
%% 3.4
numD = [1 1];
denD = [4 7 -2];
GD = tf(numD,denD);
%% 5
%% 5.1
numA = [1];
denA = [1 3 2 0];
GA = tf(numA,denA);
%% 5.2
numB = [1];
denB = [1 1 -2 0];
GB = tf(numB,denB);
%% 5.3
numC = [1];
denC = [1 2 0 0 0];
GC = tf(numC,denC);
%% 5.4
numD = [1];
denD = [1 4 3];
GD = tf(numD,denD);
%% 6
%% 6.1
numA = [1];
denA = [1 4 0 0 0];
GA = tf(numA,denA);
%% 6.2
numB = [1 2];
denB = [1 2 8];
GB = tf(numB,denB);
%% 6.3
numC = [1 -1 -2];
denC = [1 7 13];
GC = tf(numC,denC);
%% 6.4
numD = [1];
denD = [1 -1 -2 0];
GD = tf(numD,denD);
Thanks
댓글 수: 6
David Goodmanson
2021년 3월 17일
Hi Xaris,
does the final value theorem apply here?
Paul
2021년 3월 18일
Assuming that f(t) is the impulse response of G(s), what properties of G(s) determine the behavior of f(t) as t -> inf? I'm assuming that t(s) = inf means t -> inf, not sure what t(s) = inf would mean otherwise.
David Goodmanson
2021년 3월 18일
편집: David Goodmanson
2021년 3월 18일
It's the Final Value Theorem for the Laplace Transform. Look it up! ;-)
Paul
2021년 3월 18일
I'm not sure if you're saying that the FVT is the way to solve the problem or if the FVT is somehow related to the t(s) = inf. If the latter, what exactly does t(s) = inf mean?
David Goodmanson
2021년 3월 18일
I assumed that in the question, G(s) is the laplace transform of f(t). And I assumed that the question meant: based on your knowledge of G(s), what happens to f(t) as t --> inf? I bypassed the notation t(s) because I did not know what that means.
Ah, now I see our disconnect. I thought the OP wants to know "how to define the stability of a Transfer Function." The question then goes on to state that stability of G(s) is defined by the properties of f(t) (which I too assume is the inverse Laplace transform of G(s), which by all rights should be called g(t)).
So I assumed the question is to determine (not define) the external stability of the system represented by the transfer function G(s) from the properties of G(s) s.t. the properties of G(s) are consistent with the stability definitions as given by the three criteria on f(t) (which aren't quite right either). In this light, I don't believe the FVT applies, because the FVT assumes certain conditions on G(s), and verifyhing whether or not those assumptions hold is basically (with one exception) the answer to the question (as I interpreted it).
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