Display strings and variable - cell array

I want to disply the output of my variable. so i created the following code.

food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }';
X % X is the output

for n =1:length(X)
    disp(food{X(ii)})
end

The code is not working. Any help will be appreciated.

Answer 1

[ANKUR KUMAR]

Access the contents of cells by indexing with curly braces, {}.

food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }';

for n =1:length(food)
    disp(food{n})
end

[Telema Harry]

Thank you for your feedback. I have not assigned anything to the cell.

X currently contains the values of my output variable. And each index corresponds to an index in the array food. Assuming X = [1;2;3;4;5]; I want to display the following

Rice = 1;

Quinoa = 2

Tortilla = 3

Lentils = 4

Broccoli = 5;

Assigning variable X to food will probably be the best way to do it. So how can I assign X to food?

[ANKUR KUMAR]

It is not necessary to assign X to food.

If you have specific indices in X to choose from food variable, you can use this chunk of code

food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }
X=[2,5]    

for n =1:length(X)
    disp(food{X(n)})
end

[Telema Harry]

i am getting error. Don't know why? Please see screenshot.

[ANKUR KUMAR]

Please clear all the pre defined variables before running the code.

Index cannot be float. It must be an integer.

Below is the working complete code.

clc
clear
food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }
X=[2,5]    
for n =1:length(X)
    disp(food{X(n)})
end

[Telema Harry]

Thanks for the feedback. The code did work. However this is not the outcome I wanted.

I wanted to display, values of my X variable. X values are output from my optimization function.

Each index of my X(i) corresponds to same index in the food array.

Displaying only the values of X(i), one will not know the food associated with it. That is why i want to display the string i.e. food. associated with the value of X.