필터 지우기
필터 지우기

what is wrong with my 'While' function

조회 수: 1 (최근 30일)
ameen
ameen 2013년 5월 29일
i want to increase (n) until TT=s
v=0.5;
d=0.1;
density=1000;
w=0.446;
t=0.2;
rr=30.494*v^5-86.479*v^4+89.045*v^3-34.023*v^2+6.6418*v;
va=v*(1-w);
s=rr/(1-t);
n=1;
while n>1;
n=n+1;
j=va/(n*d);
kt=0.392*(1-(j/0.95))^0.8;
TT=kt*density*n^2*d^4;
if TT=s;
break
end
end
This is my program.... when i run it i received this error message '>> T=T Undefined function or variable 'T'.'

채택된 답변

Ilham Hardy
Ilham Hardy 2013년 5월 30일
편집: Ilham Hardy 2013년 5월 30일
I ran your code and found:
- Matlab is about precision, in terms that your while loops only break if the TT value is exactly the same as s. So the script will executes until n<12000 instead of stopping at the desired vessel speed. To circumvent the problem, check your script well! and use no exact value but a tolerance as shown by Azzi above.
- DO NOT name your variable i or j
- the variable n is usually expressed in rps instead of rpm.
See the code below
v=0.5;
d=0.1;
density=1000;
w=0.446;
t=0.2;
rr=30.494*v^5-86.479*v^4+89.045*v^3-34.023*v^2+6.6418*v;
va=v*(1-w);
s=rr/(1-t);
n=1;
while n<12000;
n=n+1;
j_=va/(n*d);
kt=(0.392*(1-(j_/0.95)))^0.8;
TT=kt*density*n^2*d^4;
if TT>=(s-0.5) && TT<=(s+0.5) ; %example
break
end
end

추가 답변 (4개)

Azzi Abdelmalek
Azzi Abdelmalek 2013년 5월 29일
편집: Azzi Abdelmalek 2013년 5월 29일
n=1;
while n>1;
You will never be in the loop
Also, there is no variable T in your code
To test if TT is equal to s use
if TT==s
% or
if abs(TT-s)<=tolerence %or if abs(TT-s)>=tolerence

Matt J
Matt J 2013년 5월 29일
The error message is not being triggered by any of the lines you've shown. The command T=T appears nowhere in your posted code.
I suspect you meant to type this
>>TT,
but accidentally typed this
>>T=T,

Image Analyst
Image Analyst 2013년 5월 29일
Lots and lots wrong with that code. First of all the line TT=s. It would normally be TT==s, except for the FAQ: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F so let's get rid of that line totally - you don't even need it because we'll put the stopping condition on the while line, like I'll show you later.
Next, kt is complex number. Is that what you expected? So now TT is complex. That combined with my previous comments suggests something like
n=1;
TT = -inf;
while abs(TT) < s
n=n+1;
j=va/(n*d);
kt=0.392*(1-(j/0.95))^0.8;
TT = kt*density*n^2*d^4
end
but I think that's not what you want. Another thing to do with while loops is to put in a failsafe to prevent runaway infinite loops. Like a check on n, where you'll break if it's greater than a million, or whatever you think is the greatest number n will ever possibly get to.
while abs(TT) < s && n < 1000000
So fix all those things, post your new code, and then let's continue if you're still having problems.
  댓글 수: 11
Image Analyst
Image Analyst 2013년 5월 30일
편집: Image Analyst 2013년 5월 30일
j = 1.385 the first time into the loop. So, if I plug that in for j to the command line, look what that does to kt:
K>> kt=0.392*(1-(1.385/0.95))^0.8
kt =
-0.1698 + 0.1233i
kt is complex!
Ilham Hardy
Ilham Hardy 2013년 5월 30일
Yes, you are correct for n = 2, but when n>2, parameter j becomes smaller than 1, which makes kt no longer complex.

댓글을 달려면 로그인하십시오.


ameen
ameen 2013년 5월 30일
Thank you all very much for your help and replys

카테고리

Help CenterFile Exchange에서 Programming에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by