How to track indices of a matrix after a transformation

조회 수: 6 (최근 30일)
xplore29
xplore29 2013년 5월 26일
답변: Benoit Espinola 2019년 4월 4일
I have a mxn matrix A that is transformed in some way to formulate B. The transformation can either be simple rotation or some other combination of transformations like flipud(rot(A,90)) etc. I am looking for some way to track the indices of A after any such transformation.
For Example
A = [1 2 3; 4 5 6; 7 8 9]
B = rot(A,90) = [3 6 9;2 5 8;1 4 7]
Original_Index = [1 1;1 2;1 3;2 1;2 2;2 3;3 1;3 2;3 2] (Orginal_Index is a 9x2 matrix that contains the row col indices of entries of A in Row Raster manner)
Transformed_Index = [3 1;2 1;1 1;3 2;2 2;1 2;3 3;2 3;1 3] (Also a 9x2 matrix which stores the row col indices of the entries after transformation)
I would appreciate any help in this regard.

채택된 답변

Image Analyst
Image Analyst 2013년 5월 26일
Just make a matrix of the linear indexes and do the same thing to it that you do to your main matrix and you'll always know where the original element went to.
m = magic(6) % Sample data.
% Get rows and columns.
[rows, columns] = size(m)
% Construct a map of where the elements started out.
linearIndexes = reshape(1:numel(m), [rows columns])
% Do something to the matrix.
mRot = flipud(m)
% Do the same thing to the linear indexes.
newLinearIndexLocations = flipud(linearIndexes)

추가 답변 (2개)

Azzi Abdelmalek
Azzi Abdelmalek 2013년 5월 26일
A = [1 2 3; 4 5 6;7 8 9]
idx=1:numel(A) % the index of A
B=rot90(A);
idx1=reshape(idx,size(A))
new_idx=rot90(idx1);
new_idx=new_idx(:);

Benoit Espinola
Benoit Espinola 2019년 4월 4일
I had the same issue and cameup with this:
M = [1 2 3; 4 5 6; 7 8 9; 10 11 12];
m = reshape(M, numel(M),1);
x = reshape(repmat(1:size(M,1) ,size(M,2),1), numel(M),1);
y = reshape(repmat(1:size(M,2),size(M,1),1)', numel(M),1);
In my problem, I need to keep track of the original indices of the values in the original matrix (as they were keys for something else). Here x and y keep track of the original position, so m(1) was at position x(1) for columns and y(1) for rows.
I am sure there must be a better way to do it and I am not sure how this behaves in matrices with more dimensions.

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by