필터 지우기
필터 지우기

Convert xy Coordinates to Matrix

조회 수: 21 (최근 30일)
John
John 2013년 5월 26일
댓글: Image Analyst 2021년 3월 24일
I have an xy coordinates positions (100x2) and another z vector (100x1) with values corresponding to each xy coordinate. How can I make a matrix of the coordinates with the position of each coordinate having the corresponding z value? Thanks!

채택된 답변

Andrei Bobrov
Andrei Bobrov 2013년 5월 27일
편집: Andrei Bobrov 2013년 5월 27일
after John's comment in Image Analyst's answer:
out = accumarray([x(:),y(:)],z(:),[10 10]);
or
out = zeros(10);
out(sub2ind(size(out),x,y)) = z;
  댓글 수: 4
John
John 2013년 5월 27일
Now I get it, thanks for the clarification.
cecilia dip
cecilia dip 2016년 11월 28일
Hi, I have to do the same thing, and i've tried this, but my coordinates (x,y) are negative and non-integer numbers, as they are latitude,longitude.. how can i do this? I want a plot where for each(lat,long) i can have my Z value (in a color scale, as i will compare it with interpolation methos later). Thank you!

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

Image Analyst
Image Analyst 2013년 5월 26일
Try this:
% Setup / initialization.
% Start out matrix as zeros.
m = zeros(20,10);
% Generate 100 random coordinates.
xy = int32(randi(10, 100, 2));
% Get matrix values for those x,y locations
z = randi(255, 100, 1); % 100 values.
% Now, do what the poster, John, wants to do.
% Assign the z values to the (x,y) coordinates at the corresponding row.
% E.g. m at (x(1), y(1)) will have a value of z(1).
% m at (x(2), y(2)) will have a value of z(2). And so on.
indexes = sub2ind([20, 10], xy(:,1), xy(:,2))
m(indexes) = z
  댓글 수: 6
Luigi Izzo
Luigi Izzo 2021년 3월 24일
what about if xy(k,1) or xy(k,1) are negative numbers?
Thanks
Image Analyst
Image Analyst 2021년 3월 24일
Try using a scatteredInterpolant. Demo attached.
If you still need help, attach your x, y, and z data in a new question (not here) so people can help you.

댓글을 달려면 로그인하십시오.


Annisa Dewanti Putri
Annisa Dewanti Putri 2018년 7월 10일
thanks for the help

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by