How do I make a lower triangular matrix from a column vector?
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I am trying to make a lower triangular matrix from a column vector to then produce a fully populated 24x24 symmetric matrix.
The column vector I'm using (A as a simple example) has 300 elements and I need to populate the triangular matrix (B as a simple example) as follows:
A = [i1 i2 i3 i4 i5 i6 i7 i8 i9 i10 ...]
B = [i1; i2 i3; i4 i5 i6; i7 i8 i9 i10; ....]
Any help would be appreciated. It may be that it's easier to make the symmetric matrix straight away, if so I'm open to suggestions. Thanks in advance.
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Jan
2021년 3월 9일
Create the symmetric matrix directly:
n = 24;
Ind = zeros(n, n);
Ind((1:n) >= (1:n).') = 1:300;
Ind = Ind + Ind.' - diag(diag(Ind));
B = A(Ind);
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Rik
2021년 3월 9일
The functions you should be looking for are tril and triu. You should be using triu, because you seem to want to fill your array in row-major order, while the Matlab default is column-major.
A=1:21;%replace with your data
%sz will only be a positive integer if numel(A) is a triangle number
sz=-0.5+sqrt(0.25-4*0.5*-numel(A));
B=triu(ones(sz));
B(logical(B))=A;
B=B.';
disp(B)
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Rik
2021년 3월 29일
Similar to Jan, my Python skill are only rudimentary. If you are an actual Python user, your success in googling documentation will probably be higher.
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