How to find index in cell array to start cumsum

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Jonathan Cheong
Jonathan Cheong 2021년 3월 7일
편집: Jonathan Cheong 2021년 3월 8일
Hello, I have a cell array 'ddvaluecell'.
I would like to find the index of values in these cells which are > 0.5.
Then starts a cumsum for the next 5 indices or stop early when it reaches 3.
How do I do this?
  댓글 수: 5
Walter Roberson
Walter Roberson 2021년 3월 7일
Also take the time to decide what you want to do if there are multiple nearby values that meet the test. Do you want to process separately for each possible starting point Do you want to bundle all of the values within a window of 5 together only making one start for the window? Even if the sum ends early? Do you want to bundle all consecutive >½ together but only take starting from the first of the group?
Jonathan Cheong
Jonathan Cheong 2021년 3월 7일
Thanks for the suggestion, I'll give it a go

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Jonathan Cheong
Jonathan Cheong 2021년 3월 8일
편집: Jonathan Cheong 2021년 3월 8일
Ok, so this is the answer.
% Index of starting cumsum
indices = cellfun(@(C) find(C>0.5), ddvaluecell, 'uniform', 0);
indexes = cellfun(@(x,ii) x(ii),ddindexcell,indices, 'uniform', 0);
% Change cell into array
indexarray = padcat(indexes{:}); % Pad rows with PADCAT function
indexarr = indexarray(:).'; % Change into column form
indexarr = indexarr(~isnan(indexarr)); % Remove all NaN
sumsum = zeros(0,size(rain,2));
indsum = [];
indend = [];
for bi = indexarr % Iterate over start indices (1x140)
cs = cumsum(rain(bi:end));
csp = find(cs <= 2.5); % Stop when reach 2.5mm
if numel(csp) <= 5 % Cumsum less than 5 days is used
inds3_5 = bi-1 + csp;
sumsum = [sumsum;rain(inds3_5,:)]; % append data
indsum = [indsum; inds3_5]; % append indices
ddearly = [indsum, sumsum]; % Index and value side by side
indend = [indend; inds3_5(end)]; % Last index of cumsum
end
end
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Walter Roberson
Walter Roberson 2021년 3월 8일
Can we assume that rain is Non-negative and never nan?
Jonathan Cheong
Jonathan Cheong 2021년 3월 8일
Yes, rain is never negative.
Good point, I'll change the sum variable to something else.

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