COORD = [0 0;2 0;4 0;2 2;0 2];
CON = [2 1;3 2;3 4;2 4;4 1;4 5];
for a = 1:6
i = CON(a,1);
j = CON(a,2);
COORD(j,1);
COORD(i,1);
dx = COORD(j,1)-COORD(i,1);
dy = COORD(j,2)-COORD(i,2);
lambdax(a) = dx ;
lambday(a) = dy ;
end
for a = 1:6
K = [lambdax(a)^2 lambdax(a)*lambday(a) -lambdax(a)^2 -lambdax(a)*lambday(a);lambdax(a)*lambday(a) lambday(a)^2 -lambdax(a)*lambday(a) -lambday(a)^2;-lambdax(a)^2 -lambdax(a)*lambday(a) lambdax(a)^2 lambdax(a)*lambday(a);-lambdax(a)*lambday(a) -lambday(a)^2 lambdax(a)*lambday(a) lambday(a)^2]
end
Hello everyone, this is my script it is working now but i need K in the form of K(a) or K(b), if i write K(a) it is not working. How can i write like K(a)?

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Star Strider
Star Strider 2021년 3월 6일

0 개 추천

I still do not understand what you want to do, however it is straightforward to create ‘K’ as an anonymous function:
K = @(a) [lambdax(a).^2 lambdax(a)*lambday(a) -lambdax(a).^2 -lambdax(a).*lambday(a);lambdax(a).*lambday(a) lambday(a).^2 -lambdax(a).*lambday(a) -lambday(a).^2;-lambdax(a).^2 -lambdax(a).*lambday(a) lambdax(a).^2 lambdax(a).*lambday(a);-lambdax(a).*lambday(a) -lambday(a).^2 lambdax(a).*lambday(a) lambday(a).^2];
That should then produce whatever it is that you want from calling ‘K’ as a function.
See the documentation section on Anonymous Functions for details on how they work and how to use them.
I also vectorised ‘K’. See Array vs. Matrix Operations for those details.
.

댓글 수: 6

fatih ayça
fatih ayça 2021년 3월 6일
In my script there is 6 K but it defined last one to K, i want that i ve K(1),K(2)...K(6)
Star Strider
Star Strider 2021년 3월 6일
In my script there is 6 K but it defined last one to K, i want that i ve K(1),K(2)...K(6)
I have absolutely no idea what that means.
I cannot go further without knowing what ‘lambdax’ and ‘lambday’ are. They need to be defined, regardless of whether they are functions or arrays.
fatih ayça
fatih ayça 2021년 3월 6일
편집: fatih ayça 2021년 3월 6일
I editted again,lambdax and lambday has 6 different values. So there are 6 value for K, but this script define last one for K, i want call K with 6 different value. Sorry for my bad english.
It would be easiest to define ‘K’ as a cell array in the loop:
K{a} = [lambdax(a).^2 lambdax(a).*lambday(a) -lambdax(a).^2 -lambdax(a).*lambday(a);lambdax(a).*lambday(a) lambday(a).^2 -lambdax(a).*lambday(a) -lambday(a).^2;-lambdax(a).^2 -lambdax(a).*lambday(a) lambdax(a).^2 lambdax(a).*lambday(a);-lambdax(a).*lambday(a) -lambday(a).^2 lambdax(a).*lambday(a) lambday(a).^2];
Then to get the values for ‘K{1}’ for example:
K1 = K{1}
producing:
K1 =
4 0 -4 0
0 0 0 0
-4 0 4 0
0 0 0 0
and so for the rest.
fatih ayça
fatih ayça 2021년 3월 6일
Thank you so much.
Star Strider
Star Strider 2021년 3월 6일
As always, my pleasure!

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