Equation in a single column matrix?

I wanted to compute an equation in (n,1) matrix instead of (1,n) in a for loop.

Given

a =[27.7847; 31.1386,33.3644; 37.0654; 38.5043; 41.3808];

b = [13; 33; 55; 155; 245; 519];

When I use the following for loop, it gives me 6x6 matrix instead of 6x1.

for n = 1:6

c(n)= a(n)*0.4/(log(b(n/13));

end

Please modify the equation so that I can get answers in 6x1.

Thanks in advance.

Answer 1

[Jorg Woehl]

When I run your code (after fixing a typo when you refer to what I think should be b(n)/13), the result is a 1-by-6 array for c:

a =[27.7847; 31.1386; 33.3644; 37.0654; 38.5043; 41.3808];
b = [13; 33; 55; 155; 245; 519];
for n = 1:6
    c(n)= a(n)*0.4/(log(b(n)/13));
end

c =

       Inf   13.3705    9.2526    5.9820    5.2453    4.4894

To get c as a 6-by-1 vector instead, use c(n,1) inside the loop, or calculate the transpose c=c' after the loop is done.

Or even better, avoid the for loop altogether with the following vectorized assignment:

 c = a.*0.4./(log(b./13))

This evaluates the expression one element at a time for a and b and constructs the vector c from the individual results.

[Shinichiro Shimata]

Thank you,