Finding the position of a row vector in an array

Hi

I have a 1x127 row vector in variable S and have read a 500x127 array from excel spreadsheet into variable V. Then i'm checking if S exists in V using function ' ismember '. If it returns a value 1, I need to find the location of S in the excel spreadsheet and then replace it by new vector Y.

For example:

Consider a small array,

A=[1 0 1 1 1;
   1 1 0 1 0; 
   1 0 1 1 0; 
   0 1 0 1 1; 
   0 0 1 0 1];

S=[1 0 1 1 0];

val=ismember(S,A);

Y=[1 1 1 1 1];

This will return 1. Now how can I find the location of [1 0 1 1 0] which is 3rd row here and then insert Y inplace of [1 0 1 1 0] in A, so that the modified matrix will be:

A=[1 0 1 1 1;
   1 1 0 1 0; 
   1 1 1 1 1; 
   0 1 0 1 1; 
   0 0 1 0 1];

I want to know the location of S in A considering S as one single entity.

Thank you.

Answer 1

[Azzi Abdelmalek]

[idx,idx]=ismember(A,[1 0 1 1 0],'rows')
A(logical(idx),:)=[1 1 1 1 1]

[Rekha]

Thank you...